Let $K$ be a field of characteristic $0$; let $\ell$ be any prime; and let $\mathrm{Mot}(K, \mathbb{Q}_{\ell})$ be a *Tannakian* category of motives over $K$ with coefficients in $\mathbb{Q}_{\ell}$. So, we may assume some conjectures which imply that our category of motives (defined with respect to any equivalence relation on cycles) is Tannakian, or we may apply the construction of Ives André to get the category of "motivated" motives, which is known to be Tannakian. We may choose the étale cohomology realization functor taking $\mathrm{Mot}(F, \mathbb{Q}_{\ell})$ to the category of graded $\mathbb{Q}_{\ell}$-vector spaces as our fiber functor. Then we have the *motivic Galois group* $G_{\mathrm{mot}, F}$, which is an algebraic group over $\mathbb{Q}_{\ell}$ yielding an equivalence between $\mathrm{Mot}(K, \mathbb{Q}_{\ell})$ and the category of graded $G_{\mathrm{mot}, K}$-representations. In particular, for any smooth projective variety $X$ over $K$, the group $G_{\mathrm{mot}, K}$ acts on each piece $H_{\mathrm{ét}}^i(X_{\bar{K}}, \mathbb{Q}_{\ell})$ of the étale cohomology.

Meanwhile, the absolute Galois group $\Gamma_K$ acts on each $H_{\mathrm{ét}}^i(X_{\bar{K}}, \mathbb{Q}_{\ell})$ as well. Now $G_{\mathrm{mot}, K}$ and $\Gamma_K$ are related by a quotient map induced by the embedding of the category of Artin motives into $\mathrm{Mot}(K, \mathbb{Q}_{\ell})$. I believe this quotient map admits a section $\Gamma_K \hookrightarrow G_{\mathrm{mot}, K}$ induced by the functor from $\mathrm{Mot}(K, \mathbb{Q}_{\ell})$ to Artin motives given by applying $\pi_0$ (or the $0$th cohomology).

My question is, how are the two actions on étale cohomology compatible? I believe that the action of the absolute Galois group factors as the composition of the section $\Gamma_K \hookrightarrow G_{\mathrm{mot}, K}$ with the action of the motivic Galois group, but how do I prove it? Is it explicitly proven somewhere in the literature? Is there some aspect of my construction of the question which is fuzzy? I would appreciate any imput.