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I was trying to calculate the number of points of the curve $E:y^2 = x^3 + 4x^2 + 2x$ over $\mathbb{F}_p$ for $p\equiv 1\bmod 8$ (In order to have $\sqrt{-2}\in\mathbb{F}_p$) but I did not succeed. This curve is mentioned in Silverman's Advanced Topics in the Arithmetic of Elliptic curves (Proposition 2.3.1) to have multiplication by $\sqrt{-2}$.

Over these primes $p\equiv 1\bmod 8$ the curve $E$ has full $2$-torsion so $E(\mathbb{F}_p)\cong \mathbb{Z}/(2)\times \mathbb{Z}/(k)$.

In this case my conjecture is that the size will be related to the factorization of $p=(a+b\sqrt{-2})(a-b\sqrt{-2})$ over $\mathbb{Z}[i\sqrt{2}]$, that is $p=a^2 + 2b^2$. Hence, $\#E(\mathbb{F}_p)=p+1\pm 2a$ where $a$ is odd (and the sign I do not know how to choose it yet). Calculating this reminds me to the proof of the Last Entry of Gauss Tagebuch.

I would like to have an elliptic curve with CM by $\sqrt{-2}$ such that I can know the number of points in terms of $p$. Does anybody has a suggestion? or maybe another curve?

Thanks

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Sorry for self-advertisement: the question of the "sign" that one must choose (equivalently which $\pi$ or $\overline{\pi}$) is entirely answered in my book GTM239, Section 8.5.2, some of the results being due to Mark Watkins (unpublished I believe). The main idea is to show that any CM curve is equivalent in an evident sense to a "basic" CM elliptic curve with a specific equation, giving a relation between the number of points of the initial curve and the "basic" curve, and then Theorem 8.5.8 determines explicitly the number of points of that basic curve. I did not do the exercise for your specific example, but it is completely algorithmic.

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    $\begingroup$ I'm fortunate to have purchased an electronic copy of GTM239. The basic CM elliptic curve for $\mathbb{Z}[\sqrt{-2}]$ is isomorphic to $E : y^{2} = x^{3} + 4x^{2} + 2x$, and for this curve Theorem 8.5.8 gives that $a_{p}(E) \equiv 2 \pmod{8}$ when $p \equiv 1 \text{ or } 11 \pmod{16}$ and $a_{p}(E) \equiv -2 \pmod{8}$ when $p \equiv 3 \text{ or } 9 \pmod{16}$. $\endgroup$ – Jeremy Rouse Jul 7 '17 at 1:30
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    $\begingroup$ I should add that I just learnt that Rubin--Silverberg published a paper on this subject in Math Comp 2009, including proofs this time. $\endgroup$ – Henri Cohen Jul 7 '17 at 20:55
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Your conjecture is true and follows from a theorem in Cox's book ''Primes of the form $x^{2} + ny^{2}$.'' (Theorem 14.16 on page 317, although this is from the first edition.) In particular, if $\mathcal{O}$ is an order in an imaginary quadratic field, $L$ is the ring class field associated to $\mathcal{O}$ and $E/L$ is an elliptic curve, with good reduction at a degree one prime $\mathfrak{P}$ of $L$, then $\mathcal{O}/\mathfrak{P} \cong \mathbb{F}_{p}$ and $$ |E(\mathbb{F}_{p})| = p+1 - (\pi + \overline{\pi}) $$ where $\pi \in \mathcal{O}$ and $p = \pi \overline{\pi}$. [ This result was originally proven by Deuring, and in fact Deuring's result is more general. ]

Your conjecture follows by taking $\mathcal{O} = \mathbb{Z}[\sqrt{-2}]$, $L = \mathbb{Q}(\sqrt{-2})$ and $p$ to be a prime $\equiv 1 \text{ or 3 } \pmod{8}$ (which implies that $\sqrt{-2} \in \mathbb{F}_{p}$). In this case, your $\pi = a + b \sqrt{-2}$. This theorem doesn't answer the question of what the sign is in the equation $|E(\mathbb{F}_{p})| = p+1 \pm 2a$.

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  • $\begingroup$ Thank you for your proof of the conjecture. I gave the answer to @Henri Cohen because now I solved my problem. Thanks Jeremy! $\endgroup$ – Eduardo R. Duarte Jul 12 '17 at 15:32

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