3
$\begingroup$

Suppose $X$ is a $k$-variety of dimension $d$, and suppose $TX$ is its tangent bundle. Consider the (triangulated, stable $\infty$-,...) categories of perfect complexes $\text{Perf}(X)$ and $\text{Perf}(TX)$ on $X$ and $TX$, respectively. Is it true that even if $X$ is singular (but nice enough if necessary), then locally $\text{Perf}(TX)$ is equivalent to $\text{Perf}(U\times\mathbb{A}^d)$, $U$ open subscheme of $X$?

This question is motivated by the following. If $X$ is smooth, then the tangent bundle is locally an $\mathbb{A}^d$-bundle. I want a notion similar to this that works for singular schemes. Is there an obstruction that measures this defect? Going back to perfect complexes, "how far" is $\text{Perf}(TX)$ from $\text{Perf}(X)$?

Any pointers to the appropriate literature would be nice.

$\endgroup$
  • $\begingroup$ What do you mean by $TX$ for a singular scheme? $\endgroup$ – Saal Hardali May 21 '17 at 19:24
  • $\begingroup$ Take the scheme $TX$ representing the functor from schemes $Z\mapsto \text{Mor}_k(Z\times_kk[t]/(t^2),X)$, for example. $\endgroup$ – user110215 May 21 '17 at 19:38

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.