Finite Topology vs sigma Field Suppose we have a finite $\sigma$ -field $S$, of which $A$ and $B$ are member sets. Since $S$ is closed under union and complementation [by definition], it follows that $(A' \cup B')' = (A \cap B)' \in S$. From closure under complementation, we have that $A \cap B \in S$, implying that
$S$ is closed under intersections.
Does it follow that every finite $\sigma$ -field is a topology? 
 A: Yes, it is also a topology on its union, the largest member of $S$. Since $S$ is finite, the arbitrary union rquirement amounts to finite union, which you have. 
In fact,$S$ is a Boolean algebra, and since it is finite, it is isomorphic to a powerset algebra---the power set of the atoms of $S$ (the minimal non-empty elements of $S$). Every set in $S$ is a union of a finite number of these atoms. 
If these atoms are singletons, then $S$ will be the discrete topology on the underlying set. If not, however, then $S$ will clearly not separate those points, and so will not be Hausdorff and so on.
A: It is worth remarking that the analogous characterization of σ-algebras also holds in the case of countable underlying sets: 

Any σ-algebra $\mathcal{A}$ on
  a countable set $S$ is atomic.

That is, it is generated by a partition (the classes being the "atoms"). The corresponding equivalence relation is
$$s\mathcal{R}t\ \Longleftrightarrow\     (\ \forall A\in\mathcal{A}\ (s\in A \Longleftrightarrow t\in A)\ ).$$
(In other words, $s$ and $t$ are equivalent  precisely if they are not separated by sets $A \in \mathcal{A}$.)
As a consequence, any element of $\mathcal{A}$ writes uniquely as union of atoms, making $\mathcal{A}$ isomorphic to the power set $\mathcal{P}(S/\mathcal{R})$ (in particular, of course, $\mathcal{A}$ is also a topology on $S$).
It may not be obvious that the class (or atom) $[s]$ of an element $s\in S$ in the equivalence relation $\mathcal{R}$  actually belongs to $\mathcal{A}$, for it writes as an a priori non countable intersection: 
 $$[s]:=\bigcap_{s\in A\in \mathcal{A}} A$$
But one can also write it as a countable intersection
 $$[s]:=\bigcap_{t\in S} A_{s,t} ,$$
where { $A_{s,t}$ }$_{(s,t)\in S\times S}$ is a collection of elements of $\mathcal{A}$ chosen so  that for any $(s,t)$ one has    
$A_{s,t}= S\ $ if $\ s\mathcal{R}t,$ 
$s\in A_{s,t}\ $  and $\ t\notin  A_{s,t}$ otherwise. 
The above characterization has some foundational relevance in Probability: dealing with a discrete random variable $X:\Omega\to E$ (or a finite family of them) if we please we may assume with no loss of generality that the base probability space $\Omega$ is $\mathbb{N}$.
