Asymptotics of Bessel functions With $J_n$ standing for the Bessel function of first kind, $n\in \mathbb N$, I define
$$
f_n
(\rho)
=\int_0^π J_n(\rho \sin \theta) \sin \theta \ d\theta.$$
Assuming
$1\ll\rho\ll n$, I would like to find an equivalent of $f_n(\rho)$. Is it a straightforward consequence of the known expansions?
 A: We could just take the large-$n$ asymptotic of $J_n(z)\rightarrow (2\pi n)^{-1/2}(ez/2n)^n$, and then
$$f_n(\rho)\rightarrow \frac{1}{n}(\tfrac{1}{2}e\rho/n)^n.$$
This seems to be quite reasonable in the desired range $1\ll\rho\ll n$:

blue is the exact result, gold is the asymptotic expression, plotted as a function of $n$ for fixed $\rho=10$.
A: Large-n asymptotic expansions of the Bessel functions themselves have been derived by Olver and Temme. See http://dlmf.nist.gov/10.20 and http://dlmf.nist.gov/10.19 for formulas and citations. For practical purposes, they are very complicated and onerous to derive and evaluate, and they don't converge very quickly unless n is in the tens of thousands or above.
Given Robert Israel's result, the large-n expansion for $f_n(\rho)$ is just going to be an order-by-order multiplication of terms from the large-n Bessel expansions, and unless a dramatic simplification occurs, they are going to be complicated and onerous, too. I suggest you do the first two terms and see.
