complex polynomials and inequalities Let $z_1,z_2,\dots,z_n\in\Bbb{C}$ be distinct and $w_1,w_2,\dots,w_n\in\Bbb{C}$ be arbitrary. Suppose $f, g$ are two polynomials of degree less than $n$ such that
$$f(z_j)=w_j,\qquad g(z_j)=\bar{w}_j \qquad\text{for $1\leq j\leq n$}.$$
Define $\Omega(z)=\prod_{j=1}^n(z-z_j)$. The following puzzles me.

Question 1. Is this true?
  $$\sum_{k=1}^n\frac{\vert f^{\prime}(z_k)\vert^2}{\vert \Omega^{\prime}(z_k)\vert^2}\leq
\sum_{k=1}^n\frac{\vert g^{\prime}(z_k)\vert^2}{\vert\Omega^{\prime}(z_k)\vert^2}.$$

EDIT. I'm sorry, one of the conditions was missing. To give credit, I'll leave the question as it stands and ask the correct one below.

Question 2. What if we insist that $f$ and $g$ have equal degrees?

 A: For $n\ge 3$, let's take  $z_j$,  for   $1\le j\le n$, be the $n$-th roots of unity, and $w_j:=z_j+4\bar{z_j}$, so that the assumption are satisfied by $$f(z):=z+4z^{n-1}$$ $$g(z):=4z+z^{n-1}.$$ However, 
$$  |g'(z_k)|=|4+(n-1)  z_k^{-2}|  \le n+3<\phantom{Z} $$ $$ \phantom{ZZZZ} <4n-5\le|1+4(n-1)  z_k^{-2}|= |f'(z_k)| $$ for any index $k$ in the sums. 
Rmk. For $n=2$, $f$ and $g$ are affine functions, with $|f'|=|g'|={|w_1-w_2|\over |z_1-z_2|}$, so that the claim is true. 
A: This Matlab program shows that your conjecture is in general not true for $n\geq 3$
n = 3;

z = rand(1, n) + 1i * rand(1, n)
w = rand(1, n) + 1i * rand(1, n)

f = polyfit(z, w, n-1);
g = polyfit(z, conj(w), n - 1);

% note that Omega(z_i) = 0 and Omega(z) = z^n+q(z) where deg(q)<=n-1 and
% hence q(z_i)=-z_i^n
Omega = [1 -polyfit(z, z.^n, n - 1)];

df = polyder(f);
dg = polyder(g);
dOmega = polyder(Omega);

adf = abs(polyval(df, z));
adg = abs(polyval(dg, z));
adO = abs(polyval(dOmega, z));

sum((adf./adO).^2)-sum((adg./adO).^2)

