If I have a known matrix A, is there a method to find a matrix B that share all the eigen vectors of Matrix A?
1 Answer
$\begingroup$
$\endgroup$
1
Any analytic function of $A$ (including such diverse ones as $p(A),$ where $p$ is a polynomial, and $\exp(A)$) will work.
-
2$\begingroup$ Moreover, if $A$ has all distinct eigenvalues then all solutions will be of that form. $\endgroup$ Commented Dec 19, 2016 at 16:21