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Q: Which prime number is divisible by 2 3 4 and 5?

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Neither number is prime: 117 is divisible by 3 and 84 is divisible by 2.

Yes. If a number is evenly divisible by both 3 and 4, it will also be divisible by 6.This is because the prime factor of 3 is [3] -- in other words, 3 is a prime number -- and the prime factors of 4 are [2, 2].Thus, any number that is divisible by 3 and 4 will have as part of its prime factors the set [2, 2, 3]. (The smallest such number is 12, which is 2 x 2 x 3.) Since the prime factors of 6 are [2, 3] -- and [2, 3] is a subset of [2, 2, 3] -- then any such number must also be divisible by 6.Another way to look at it is to note that all numbers which are divisible by both 3 and 4 are also divisible by 12 (which is 3 x 4). Since 12 is divisible by 6, then all multiples of 12 will also be divisible by 6.

A prime number is divisible only by 1 or itself.

56 is not a prime number as it is divisible by 2. The only even prime number is 2. And its not divisible by 3, except with a remainder.

Because any number divisible by 2 is not a prime number, so any even no. is divisible by 2. Thus any number higher than 3 will be divisible by 2. Therefore the only consecutive prime nos. are 1, 2 and 3

2 is a prime number. It is only evenly divisible by itself and one.3 is a prime number. It is only evenly divisible by itself and one.5 is a prime number. It is only evenly divisible by itself and one.

2 is a prime number. It is only evenly divisible by itself and one.3 is a prime number. It is only evenly divisible by itself and one.

No, it is divisible by 2 and 3.

First we have to find a prime number by which 18 is divisible. 18 is divisible by both 2 and 3. However, we can start with any number. 18/3 = 6, now we have to look for a prime number by which 6 is divisible. 6/3 = 2, 2 is divisible by itself. So, prime factorization of 18 = 2x3x3.

There is only one prime number divisible by 3 and it is 3 itself which is a prime number.

The number 2359 is divisible by 7 and therefore not prime.

If the number has a remainder of 2 or 4 when divided by 6, it is an even number, so it is not prime number. 6n + 2 = 2 (3n + 1), so it is divisible by 2. 6n + 4 = 2 (3n + 2), so it is divisible by 2. If the number has a remainder of 3 when divided by 6, it is divisible by 3, so it is not a prime number. 6n + 3 = 3 (2n + 1), so it is divisible by 3. However, there are two prime numbers that do not have a remainder of 1 or 5 when divided by 6 : 2 and 3

A prime number has only 2 factors which are 1 and itself. Composite numbers are everything else except 1 and 0. 1 and 0 are neither prime, nor composite. A prime number is not divisible by 3.

A prime number is not divisible by any numbers except 1 and itself. A composite number is divisible by other numbers. 9 is divisible by 3, so it is a composite number.

54 is divisible by 2 and 3 which are prime numbers

6 is not a prime number b\c, it is divisible to 2 and 3

No. 108 is composite because it is evenly divisible by 2 and 3, as well as by other products of 2 and 3. In order to be prime, a number must be evenly divisible only by 1 and itself.

As an even number greater than 2, 618 is divisible by 2 and therefore not a prime number.No, 618 is not a prime number, as it can be divided by 3.

No, because it is divisible by both 2, 3, 6 and 9, as well as with 1 and itself. A prime number is only divisible by 1 and itself.

21 has factors other than 1 and itself, so it is not a prime number. For example, it is divisible by 3. (You can check this by adding the digits of the number: 2 + 1 = 3. If the sum of the digits is divisible by 3, the number is also divisible by 3.) Therefore, 21 is a composite number.

No number that is a multiple of 3, can be a prime number. A prime number must only be divisible by itself and 1. It cannot be divisible by any other number. Therefore if it is a multiple of 3, then it must be divisible by 3 and hence, not a prime number.

You can check each individual number, whether it is a prime number. For numbers below 100, it is enough to check whether they are divisible by 2, by 3, by 5, and by 7. If a number is divisible by none of these, it is a prime number.

No, this number is divisible by 3 and hence is not a prime number. You can tell that fast by adding the individual digits. If that sum is itself divisible by 3, as this one is, then the number itself is divisible by 3.

3 <><><> 3 is only divisible by 1 and itself. whereas 4 and 10 are divisible by other numbers. 4 is divisible by 1,2,4. 10 is divisible by 1,2,5,10 <><><> A prime number is a number that is evenly divisible only by itself and one. Therefore, 3 is the prime number. 4 is divisible by 1, 2, and 4. 10 is divisible by 1, 2, 5, and 10. Three cannot be divided evenly by any other whole number. So, 3 is the prime number.

No its divisible by 1 2 3 and more