When is Sobolev space a subset of the continuous functions? If we let $\Omega\subset\mathbb{R}^d$ with $d=1,2,3$ and define $\mathcal{H}^1(\Omega)=(w\in L_2(\Omega): \frac{\partial w}{\partial x_i}\in L_2(\Omega), i=1,...,d)$. My tutor has repeated several times:


*

*If $d=1$ then $\mathcal{H}^1(\Omega)\subset\mathcal{C}^0(\Omega)$.

*If $d=2$ then $\mathcal{H}^2(\Omega)\subset\mathcal{C}^0(\Omega)$ but $\mathcal{H}^1(\Omega)\not\subset\mathcal{C}^0(\Omega)$.

*If $d=3$ then $\mathcal{H}^3(\Omega)\subset\mathcal{C}^0(\Omega)$ but $\mathcal{H}^2(\Omega)\not\subset\mathcal{C}^0(\Omega)$.


I was interested in trying to show these relationships. Does anyone know any references that would be useful. 
Thanks in advance. 
 A: If you just want the answer, then not surprisingly you can find it at:
https://en.wikipedia.org/wiki/Sobolev_inequality
If you want a careful introduction to and derivation of the Hilbert space case, see:
"Seminar on the Atiyah-Singer Index Theorem" (Princeton Univ. Press)
A: I'll give you a hint for the first one $d=1$.  Consider first the case that your function $f \in H^1([0,1])$ was smooth. Then we could say
$f(x) - f(y) = \int_{x}^y f'(s)ds$. Apply Cauchy-Schwarz now and you'll be able to see immediately that $f$ is $1/2$ Hölder continuous.
For higher dimensions you actually proceed similarly but you need to use the co-area formula.
A: I understand from your post that you'd like to show those facts by yourself first, and not necessarily to approach the whole theory now (I like your approach). Trivial hint: start with smooth functions with compact support in $\Omega$, and try to bound their $L^\infty$ norm in terms of the $H^d$ norm. Also, I suggest that you try building counter-examples by yourself for the case of non-inclusions.
Reference: Brezis' book of Functional Analysis may give you nice hints. 
A: By now, I can't remember precisely where the best places to learn this is. Here are some rather vague suggestions:


*

*I don't know if this stuff is in any of Nirenberg's writings, but if it is, it's sure to be a clear and easy approach.

*Look in books about nonlinear elliptic PDE's by, say, Craig Evans, Gilbarg and Trudinger, or Thierry Aubin.

*Ideally, there should be a proof that involves integration over cubes. Differential geometers such as Aubin tend to prove such results by integrating over balls because that's what generalizes more easily to Riemannian manifolds. That works fine but the formulas are messier than for a cube. In the end, after you get the idea of what's going on, just write out your own proof.
A: all the previous answers provide very valuable insight and lead you in the right direction. I would however just like to point out that the last of the three statements in the original question is incorrect. Consider the domain to have a $C^{1}$ boundary. The generalized Sobolev inequality states that if $k > \frac{d}{2}$ and $u \in \mathcal{H}^{k}\left(\Omega\right)$ then
$u \in u\in C^{k-\left\lfloor \frac{d}{2}\right\rfloor -1,\varrho}\left(\Omega\right)$,
where $\varrho>0$. This means in particular that if $k=2, d=3$
$u\in C^{0,\varrho}\left(\Omega\right)$,
which implies that $u \in C^{0}\left(\Omega\right)$.
So $\mathcal{H}^{3}\left(\Omega\right)\subset C^{0}\left(\Omega\right)$ is true, but so is $\mathcal{H}^{2}\left(\Omega\right)\subset C^{0}\left(\Omega\right)$.
A: This is a particular case of the Sobolev embedding theorem. I would suggest the standard book, "The analysis of Linear partial differential operators I" by Hormander (Th 4.5.13).
