The physical meaning of a Lie group symmetry is clear: for example, if you have a quantum system whose states have values in some Hilbert space $H$, then a Lie group symmetry of the system means that $H$ is a representation of some Lie group $G$. So you want to understand this Lie group $G$, and generally you do it by looking at its Lie algebra. At least initially, this is understood as a way to make the problem of classifying Lie groups and their representations easier.

But there are Lie algebras which are not the Lie algebra of a Lie group, and people are still interested in them. One possible way to justify this perspective from a physical point of view is that Lie algebras might still be viewable as ("infinitesimal"?) symmetries of physical systems in some sense. However, I have never seen a precise statement of how this works (and maybe I just haven't read carefully enough). Can anyone enlighten me?

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    $\begingroup$ One perspective is: if you have a Lie algebra of symmetries, pretend it is the Lie algebra of a group, and try to do as much as you can without ever touching the (nonexistent) group. Surprisingly, this will get you quite far lots of examples. $\endgroup$ May 17, 2010 at 8:35
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    $\begingroup$ "But there are Lie algebras which are not the Lie algebra of a Lie group". Given the physics context, I assume you mean perhaps infinite-dimensional Lie algebras over R: every finite-dimensional Lie algebra over R integrates to a group. $\endgroup$ May 17, 2010 at 16:51
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    $\begingroup$ Incidentally, not every Lie group action has a corresponding Lie algebra action. For example, consider R acting on L^2(R) by translation. The infinitesimal generator of translation is the operator d/dx --- i.e. the Lie algebra action on any function space corresponding to the group action by translation is necessarily: the basis vector of the Lie algebra acts by d/dx. But, of course, d/dx does not act on L^2(R): the derivative of an L^2 function is not L^2. $\endgroup$ May 17, 2010 at 16:53
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    $\begingroup$ Theo, there is, though, a very well developed of partially defined infinitesimal generators of groups. In the case of the translation action on L^2(R), the infinitesimal generator d/dx is closed, and that will take you very very far provided you are determined enough. $\endgroup$ May 18, 2010 at 13:47
  • $\begingroup$ Related: mathoverflow.net/questions/302765/… $\endgroup$
    – mo-user
    Sep 3, 2018 at 9:59

2 Answers 2


I'm not sure which sort of examples of Lie algebras without the corresponding groups you have in mind, but here is a typical example from Physics.

Many physical systems can be described in a hamiltonian formalism. The geometric data is usually a symplectic manifold $(M,\omega)$ and a smooth function $H: M \to \mathbb{R}$ called the hamiltonian. If $f \in C^\infty(M)$ is any smooth function, let $X_f$ denote the vector field such that $i_{X_f}\omega = df$. If $f,g \in C^\infty(M)$ we define their Poisson bracket $$\lbrace f, g\rbrace = X_f(g).$$ It defines a Lie algebra structure on $C^\infty(M)$. (In fact, a Poisson algebra structure once we take the commutative multiplication of functions into account.)

In this context one works with the Lie algebra $C^\infty(M)$ (or particular Lie subalgebras thereof) and not with the corresponding Lie groups, should they even exist.

Symmetries in this context are functions which Poisson commute with the hamiltonian, hence the centraliser of $H$ in $C^\infty(M)$. They define a Lie subalgebra of $C^\infty(M)$.


Another famous example occurs in two-dimensional conformal field theory. For example, the Lie algebra of conformal transformations of the Riemann sphere is infinite-dimensional: any holomorphic or antiholomorphic function defines an infinitesimal conformal transformation. On the other hand, the group of conformal transformations is finite-dimensional and isomorphic to $\mathrm{PSL}(2,\mathbb{C})$.

  • $\begingroup$ The second example looks more like what I want. What do you mean by a "Lie algebra of conformal transformations"? Something like locally invertible conformal maps? $\endgroup$ May 17, 2010 at 21:23
  • $\begingroup$ Oops. I didn't see this comment before now. A pair of holomorphic functions $f(z),g(z)$ defines an infinitesimal conformal transformation $z \mapsto z + f(z) + \overline{g(z)}$. They generate the Lie algebra of conformal transformations. It is in fact isomorphic to two copies of the algebra of diffeomorphism of the circle. $\endgroup$ May 31, 2010 at 16:43
  • $\begingroup$ Can you explain further? As I understand it (as a topologist not a physicist), smooth tangent vector fields on a manifold correspond to local flows = "infinitesimal actions" of the group of real numbers. The Lie algebra of all vector fields corresponds in a sort of formal sense to the group of all diffeomorphisms. One can speak of the Lie subalgebra preserving some tensor field (meaning that the Lie derivative vanishes), and this structure corresponds in the same way to local diffeomorphisms preserving it. This fits with your discussion of the Hamiltonian setup, but ... $\endgroup$ Jun 23, 2010 at 4:14
  • $\begingroup$ ... in case of conformal structure I would think that the vector fields preserving that structure correspond naturally to the holomorphic sections of the complex tangent bundle, so that locally such a field corresponds to one holomorphic function -- where's the antiholomorphic one? -- and globally on the Riemann sphere they form a 3-d complex Lie algebra, that of the (finite-dimensional) global conformal symmetry group. What am I miss(understand)ing? $\endgroup$ Jun 23, 2010 at 4:20

I would like to provide you with a non-trivial example (and a reference) of a Lie algebra of symmetries which is not a Lie algebra of a Lie group within the framework of conventional quantum mechanics. This example relies on the notion of "dynamical groups" (which you can find a lot of literature about in the net). I think that the most precise definition of a dynamical group of a quantum system would be a Lie group which the system's phase space is a coadjoint orbit of. In the cases known to me the system's Hamiltonian belongs to the Lie algebra of the dynamical group, but I don't think that this is an essential requirement (The Hamiltonian can be a member of the universal enveloping algebra). The main application of dynamical groups is to provide algebraic solution to the quantum mechanical problem. The spectrum of the systems can be obtained from the representation of the dynamical group associated with the coadjoint orbit instead of solving the Shroedinger equation.

The Lie algebra of the dynamical group generally consists of the usual space time symmetries such as the angular momentum su(2) in addition to more generators which originally required a lot of ingenuity to come up with, such as the Runge-lenz generators of the Hydrogen atom problem, sometimes referred to as the Kepler problem,which close together with the angular momentum generators to o(4) for elliptical motion and o(3,1) for hyperbolic motion.

Another known example in which a dynamical group formulation is used is the harmonic oscillator with the dynamical group SU(1,1).

Returning to the Kepler problem. The treatment described above considers only a fixed energy subspaces. In the following article , by C. Dabul, J. Dabul, P. Slodowy, a twisted Kac-Moody dynamical algebra is constructed which is a simultaneous dynamical Lie algebra of the full problem (corresponding to elliptic, parabolic and hyperbolic trajectories). This is an example of a dynamical Lie algebra of symmetries which is not a Lie algebra of a Lie group.

Regrettably, I didn't see a followup of this work in terms of algebraic solution of the full Kepler problem in terms of representations of this algebra, nor a treatment of this problem in terms of coadjoint orbits of (the non-Lie) Kac-Moody groups which correspond to this algebra and are subjects of active research. I think that these would be interesting research problems.


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