22
$\begingroup$

This question was asked on MathStackexchange here, but there was no answer, so I am asking it here.

Let$$x_1 = 2, \quad x_{n + 1} = {{x_n(x_n + 1)}\over2}.$$What can we say about the behavior of $x_n \text{ mod }2$? Is there an exact formula for $x_n \text{ mod }2$?

$\endgroup$
3
  • 8
    $\begingroup$ Found it on OEIS, at least: oeis.org/A117872 $\endgroup$ Jul 17, 2016 at 19:58
  • $\begingroup$ Note that we have $x_{n+1} \equiv 0$ (mod $2$) if and only if $x_{n} \equiv 0$ or $3$ (mod $4$). $\endgroup$ Jul 17, 2016 at 21:20
  • $\begingroup$ An immediate question: Is oeis.org/A126768 a bounded sequence? $\endgroup$
    – A_S
    Jul 18, 2016 at 5:07

2 Answers 2

23
$\begingroup$

As remarked by Joe Silverman, a natural way to look at this question is by phrasing it in terms of the map $f(x):=\frac{1}{2}x(x+1)$ on the $2$-adic integers $\mathbb{Z}_2$. We are then asking about the behaviour of the orbit $f^n(2)$ with respect to the partition of $\mathbb{Z}_2$ into two clopen sets $U_1:=2\mathbb{Z}_2$ and $U_2:=1+2\mathbb{Z}_2$. Most questions of this form are very hard, for reasons which I will attempt to explain. Short answer: dynamically, there is no obvious reason why this should be easier than the Collatz problem or the normality of $\sqrt{2}$.

Suppose that we are given a continuous transformation $f$ of a compact metric space $X$ and a partition of $X$ into finitely many sets $U_1,\ldots,U_N$ of reasonable regularity (e.g. such that the boundary of each $U_i$ has empty interior). We are given a special point $x_0$ and we want to know how often, and in what manner, the sequence $(f^n(x_0))_{n=1}^\infty$ visits each of the sets $U_i$. We might believe the following result to be useful: if $\mu$ is a Borel probability measure on $X$ such that $\mu(f^{-1}A)=\mu(A)$ for every Borel measurable set $A\subset X$, and if additionally every $f$-invariant measurable set $A\subseteq X$ satisfies $\mu(A)\in \{0,1\}$, then $$\lim_{n\to\infty}\frac{1}{n}\sum_{i=0}^{n-1}\phi(f^i(x)) =\int \phi\,d\mu$$ for $\mu$-almost-every initial point $x$ and every $\mu$-integrable function $\phi \colon X \to \mathbb{R}$. This is the Birkhoff ergodic theorem or pointwise ergodic theorem. In particular we could take $\phi$ to be the characteristic function of a partition element $U_i$, so the above measures the average time spent in $U_i$ by the sequence $f^n(x)$. Or we could take $\phi$ to be the characteristic function of a set such as $U_1\cap f^{-1}U_2 \cap f^{-2}U_1$, which would tell us how often the orbit of $x$ follows the path $U_1 \to U_2 \to U_1$, and so on.

The Birkhoff theorem is great if we are content to study points $x$ which are generic with respect to a particular invariant measure. If we want to study a specific $x$ then we have no way to apply the theorem. If multiple different invariant measures $\mu$ exist then the integrals which they assign to the characterstic functions $\chi_{U_i}$ will in general be different and we will get different answers, and the Birkhoff averages along orbits will have fundamentally different behaviours depending on which measure the starting point is generic with respect to (if any). In a broad sense this is an aspect of the phenomenon called "chaos". Here is a nice example: let $X=\mathbb{R}/\mathbb{Z}$, $f(x):=2x$, let $U_1=[0,\frac{1}{2})+\mathbb{Z}$ and $U_2=X\setminus U_1$. What can we say about the manner in which the trajectory $f^n(\sqrt{2})$ visits $U_1$ and $U_2$? For example, does the trajectory spend an equal amount of time in both sets? Put another way, is $\sqrt{2}$ normal to base $2$? Dynamical methods can tell us that Lebesgue a.e. number is normal to base $2$, but they struggle badly for specific numbers. The difficulty of this problem is tied quite closely to the existence of many invariant measures for this map: Lebesgue measure is invariant, but so is the Dirac measure at $0$; there are many invariant measures supported on closed $f$-invariant proper subsets corresponding to restricted digit sets (e.g. numbers where "11" is not allowed in the binary expansion) and also many fully supported invariant measures which are singular with respect to Lebesgue measure (and indeed with respect to one another). Each invariant measure contributes a set of points with its own particular, distinct dynamical behaviour, and given an arbitrary point we have no obvious way of knowing which of these different dynamical behaviours prevails.

There is only one situation in which this dynamical problem becomes easy: when a unique $f$-invariant Borel probability measure exists. In this case the convergence in the Birkhoff theorem is uniform[*] over all $x$, and the problem of distinguishing which invariant measure (if any) characterises the behaviour of the trajectory $f^n(x)$ vanishes completely. An example would be the leading digit of $2^n$: take $X=\mathbb{R}/\mathbb{Z}$, $U_k=[\log_{10}k,\log_{10}(k+1))+\mathbb{Z}$ for $k=1,\ldots,9$, $f(x):=x+\log_{10}2$, then the leading digit of $2^n$ is $k$ if and only if $f^n(0) \in U_k$. The irrationality of $\log_{10} 2$ may be applied to show that Lebesgue measure is the only $f$-invariant Borel probability measure, and using the uniform ergodic theorem we can simply read off the average time spent in each $U_k$ as the Lebesgue measure of that interval.

So how does this affect $f(x):=x(x+1)/2$ on $\mathbb{Z}_2$? Well, $x=1$ and $x=0$ are both fixed points and carry invariant Borel probability measures $\delta_1$ and $\delta_0$. So the dynamical system is not uniquely ergodic, and the problem of determining which of the (presumably many) invariant measures characterises the trajectory of the initial point $2$ has no obvious solution.

[*] to obtain uniform convergence in this case $\phi$ must be a continuous function. By upper/lower approximation we can deduce pointwise convergence to $\int \phi\,d\mu$ for all $x\in X$ in the case where $\phi$ is upper or lower semi-continuous, for example where $\phi$ is the characteristic function of a closed or open set.

$\endgroup$
2
  • 2
    $\begingroup$ Rather than stretch my answer out even longer, I'll add a comment to justify my mentioning the Collatz problem. Let $f \colon \mathbb{Z}_2 \to \mathbb{Z}_2$ with $f(x):=x/2$ for $x \in 2\mathbb{Z}_2$ and $f(x)=(3x+1)/2$ otherwise. This map preserves Haar measure on $\mathbb{Z}_2$, among other measures. By the ergodic theorem a Haar-typical point spends exactly half its time in $2\mathbb{Z}_2$. If a point spends exactly half its time in $2\mathbb{Z}_2$ then the Collatz map applied to that point spends half its time dividing by $2$ and the other half multiplying by $3/2$ and adding $1/2$. $\endgroup$
    – Ian Morris
    Jul 18, 2016 at 12:08
  • 4
    $\begingroup$ It follows that if integers behaved like Haar-typical points then they would on average be multiplied by about $3/4$ for every two applications of the Collatz map and therefore have bounded trajectories. But unless we can somehow explain why integers should in this way behave like Haar-typical points this does not help us solve the original problem. $\endgroup$
    – Ian Morris
    Jul 18, 2016 at 12:08
13
$\begingroup$

The modern way to view this problem is as a problem in $p$-adic dynamics. In your case, you are studying the $2$-adic orbit of the point 2 under iteration of the polynomial map $f(x)=\frac12x(x+1)$. You've broken $\mathbb Z_2$ into two open sets $U_0:=2\mathbb Z_2$ and $U_1:=1+2\mathbb Z_2$, and you're asking for the itinerary $(i_0,i_1,i_2,\ldots)$ of the iterates, i.e., the list of 0's and 1's such that $f^n(2)$ is in $U_{i_n}$. Analyzing dynamical systems (both complex and $p$-adic) via itineraries is a standard tool. I don't know, offhand, the answer for your particular example, but you might find some tools and examples that would help in the papers of Liang-Chung Hsia and Rob Benedetto (for example). [You might also want to add the arithmetic-dynamics tag to your question.]

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.