Let $S$ be a surface and $\gamma$ a curve on $S\subseteq \mathbb{R}^3$ obtained cutting $S$ with a plane. I wuold an upper bound for the curvature of $\gamma$. Are there papers for this topic?
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$\begingroup$ Does the plane contain the normal direction? $\endgroup$ – Mikhail Katz Jun 14 '16 at 17:39

$\begingroup$ My surface is in the euclidean space. $\endgroup$ – Vincenzo Zaccaro Jun 14 '16 at 17:42

5$\begingroup$ Upper bounds in terms of what? $\endgroup$ – Igor Rivin Jun 14 '16 at 18:18

2$\begingroup$ You are more likely to have a lower bound. It seems to me that the curvature can grow a lot when the plane gets closer to the tangent. $\endgroup$ – Alex Degtyarev Jun 14 '16 at 18:22

$\begingroup$ For Igor...in terms of the gaussian curvature and slope of the plane respect to the gauss map. $\endgroup$ – Vincenzo Zaccaro Jun 14 '16 at 22:38
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Getting bounds from Gaussian curvature is hopeless due to examples like the pseudosphere, but assuming that the principal curvatures are at most $1$ one should be able to show that the curvature of the intersection should be bounded above by $\sec \alpha$ where $\alpha$ is the angle with the normal vector.