Let $f:X\rightarrow Y$ be a birational map of smooth projective varieties over complex numbers. Let $E$ be a vector bundle on $X$. Will $f_*E$ be a reflexive sheaf. Is it possible to impose some additional conditions to ensure that the direct image is a reflexive sheaf?

$\begingroup$ you can take double dual $(f_∗E)^{**} $. $\endgroup$ – user21574 Jun 13 '16 at 9:47

$\begingroup$ @Hassan Jolany Sorry I don't understand your comment. Can you elaborate? Even $(f_*E)^*$ will be reflexive right?. But I am interested to know when $f_*E$ itself is reflexive $\endgroup$ – gradstudent Jun 13 '16 at 9:49

1$\begingroup$ read this paper of Hartshorne gdz.sub.unigoettingen.de/dms/load/img/?PID=GDZPPN002320002 $\endgroup$ – user21574 Jun 13 '16 at 9:57

6$\begingroup$ Take for $f$ the simplest example of birational morphism, the blowing up of a point $p$ in a surface; let $E$ be the exceptional divisor. Then $f_*\mathcal{O}(E)$ is the ideal sheaf of $p$, which is not reflexive. $\endgroup$ – abx Jun 13 '16 at 10:30

1$\begingroup$ @ abx  I think your comment is so elegant you really ought to consider making it an answer so that people searching this will see it. $\endgroup$ – meh Jun 13 '16 at 14:36
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As requested I put my comment into an answer: take for $f$ the simplest example of birational morphism, the blowing up of a point $p$ in a surface; let $E$ be the exceptional divisor. Then $f_*\mathcal{O}(E)$ is the ideal sheaf of $p$, hence is not reflexive.