# Hamiltonian path in countable connected graph such that $\text{deg}(v)=\omega$ for all $v$ [closed]

Is there a countable connected graph $G=(\omega, E)$ such that $\text{deg}(v)=\omega$ for all $v\in\omega$, but there is no Hamiltonian path in $G$?

## closed as off-topic by Franz Lemmermeyer, Alexey Ustinov, Wolfgang, Boris Bukh, MyshkinMay 11 '16 at 0:23

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "This question does not appear to be about research level mathematics within the scope defined in the help center." – Franz Lemmermeyer, Alexey Ustinov, Wolfgang, Boris Bukh, Myshkin
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