12
$\begingroup$

Let G=GLn(ℂ) and let T be a maximal torus. Let X be a topological space with a G-action. My question is: when is the canonical map $$H^*_G(X;\mathbb{Z})\to H^*_T(X;\mathbb{Z})$$ injective?

Some remarks: I am trying to understand Torsten's answer here, which claims injectivity for the case where X is the space of length m quotients of $\mathcal{O}_C^m$ for a smooth proper curve C over ℂ. (there is a remark "G being special" that is especially cryptic to me and is probably where the answer lies). I am familiar with some arguments to prove injectivity when the ring of coefficients has n! invertible, but here I specifically want to consider integral coefficients.

$\endgroup$
3
  • 1
    $\begingroup$ Two things. The relevant map of spaces here is $X_T := (X \times EG)/T \to X_G := (X\times EG)/G$ with fiber $G/T$ or homotopically $G/B$. So $H^*(X_T)$ can be computed from a spectral sequence from $H^*(X_G)$. If for some reason you knew already the latter had even-degree cohomology... The other thing is that your map factors through $H^*_{N(T)}(X;\mathbb Z)$, and I suspect any kernel has to happen already there. $\endgroup$ Apr 16, 2016 at 7:21
  • 2
    $\begingroup$ This isn't a complete answer, but for example, if you know that $H_T^*(X;\mathbb{Z})$ injects into the cohomology of the fixed point set $X^T$, then (for $G=GL_n(\mathbb{C})$) the canonical map is injective. See Theorem 2.10 and Corollary 2.11 in T. Holm and R. Sjamaar, "Torsion and abelianization in equivariant cohomology." Transform. Groups 13 (2008), no. 3-4, 585–615. $\endgroup$
    – Tara Holm
    Apr 17, 2016 at 1:14
  • 1
    $\begingroup$ Thanks Tara for this useful response. If you make it an answer, I'll accept it. $\endgroup$ Apr 18, 2016 at 1:46

1 Answer 1

12
$\begingroup$

This isn't a complete answer, but for example, if you know that $H_T^*(X;\mathbb{Z})$ injects into the cohomology of the fixed point set $X^T$, then for $G=GL_n(\mathbb{C})$, the canonical map $H_G^*(X;\mathbb{Z})\to H_T^*(X;\mathbb{X})$ is injective. See Theorem 2.10 and Corollary 2.11 in T. Holm and R. Sjamaar, "Torsion and abelianization in equivariant cohomology." Transform. Groups 13 (2008), no. 3-4, 585–615.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.