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Let $\lambda$ be a partition with $\leq n$ rows and let $L_{\lambda}$ be the corresponding irreducible representation of ${\rm GL}_n(\mathbb{C})$. Let $e_m(X_1,\dots,X_n)$ be the $m$th elementary symmetric polynomial. Is there a known formula for the element $c_m \in Z(U(\mathfrak{gl}_n))$ which acts on $L_{\lambda}$ by the scalar $e_m(\lambda_1,\dots,\lambda_n)$?

It is easy to check that $c_1 = E_{11} + \dots + E_{nn}$, so I suspect that $c_m$ should be related to the coefficients of the characteristic polynomial. Also, I am aware of the Harish-Chandra isomorphism, but have not been able to use it to produce a formula.

I would be particularly interested in references where this is worked out. I couldn't find it in any of the standard representation theory text books.

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  • $\begingroup$ This kind of question has come up earlier, so it's worth looking at some of the related ones, e.g., mathoverflow.net/questions/197786/… $\endgroup$ – Jim Humphreys Mar 10 '16 at 17:15
  • $\begingroup$ I am aware of Motsak's thesis. (s)he actually gives explicit generators for $Z(U(\mathfrak{gl}_n))$ but they do not have the correct character. You could go from those generators to the ones I am looking for using symmetric function theory, but I don't think that would be easy $\endgroup$ – Daniel Barter Mar 10 '16 at 18:27
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I believe the elements of $\mathcal{Z}(\mathfrak{g})$ you are looking for are (suitably renormalised) the Capelli elements; these come from the (renormalised) Capelli determinant \[C(u) = \det\left(E_{jk} + \left(u - \frac{n - 2j + 1}{2}\right) \delta_{jk}\right),\] where by the determinant of a matrix $A = (A_{jk})$ we mean the column determinant \[\det A = \sum_{\sigma \in S_n} \mathrm{sgn}(\sigma) A_{\sigma(1),1} \cdots A_{\sigma(n),n}. \] For all $u$, $C(u)$ lies in $\mathcal{Z}(\mathfrak{g})$.

One can show that given an irreducible representation $\pi_{\lambda}$ of $\mathrm{GL}_n(\mathbb{C})$ of highest weight $\lambda = (\lambda_1,\ldots,\lambda_n)$, the Harish-Chandra isomorphism $\chi_{\pi_{\lambda}}$ acts on $\mathcal{Z}(\mathfrak{g})$ by sending $E_{jj}$ to $\lambda_j + \frac{n - 2j + 1}{2}$ and $E_{jk}$ to $0$ whenever $j \neq k$. So from the definition of $C(u)$, $\pi_{\lambda}(C(u))$ acts by the scalar \[\prod_{\ell = 1}^{n} (u + \lambda_{\ell}).\] Expanding $C(u)$ as a polynomial in $u$, we see that the coefficients of each power of $u$ are elements of $\mathcal{Z}(\mathfrak{g})$ that act by the scalar $e_m(\lambda_1, \lambda_2, \ldots, \lambda_n)$.

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