7
$\begingroup$

Let $(X, A)$ be a cofibration, with $X$ compactly generated. This is equivalent to the fact that $A$ is a NDR of $X$, i.e., there exist two functions $\phi \colon X \rightarrow I$ e $H \colon X \times I \rightarrow X$ such that $A = \phi^{-1}(\{0\})$, $H(x, 0) = x$ and $H(a, t) = a$ for every $x \in X, a \in A, t \in I$, and $H(x, 1) \in A$ for every $x \in \phi^{-1}([0, 1))$. We call $U := \phi^{-1}([0, 1))$. The definition does not imply that $A$ is a (strong) deformation retract of $U$, because it is not necessary that $H(U \times I) \subset U$. Actually, in Strom's book ''Modern classical homotopy theory'', theorem 5.20 p. 104, it is stated that $A$ is a deformation retract of $U$, but I didn't manage to prove that the function $H$, defined in problem 5.21 p. 105, satisfies $H(U \times I) \subset U$. My question is the following.

Question: If $(X, A)$ is a NDR pair and $X$ is compactly generated, is it true that $H$ and $\phi$ can be chosen in such a way that $A$ is a (strong) deformation retract of U? (This implies that $(X, A)$ is a good pair in the sense of Hatcher's book.) If not, what is a counter-example? Moreover, if the answer is negative, is there a cofibration $(X, A)$ such that $A$ is not a (strong) deformation retract of any neighborhood, even different from $\phi^{-1}([0, 1))$?

Actually, in May's book ''The geometry of iterated loop spaces'', definition A.1 p. 85, an NDR-pair is called strong if $\phi(H(x, t)) < 1$ when $\phi(x) < 1$, which is equivalent to $H(U \times I) \subset U$. Therefore my question can be formulated in the following way: is every NDR-pair (at least when $X$ is compactly generated) strong? If not, what is a counter-example?

$\endgroup$
3

0

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Browse other questions tagged or ask your own question.