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Let $m_i $, $i \in I,$ be an infinite family of maximal ideals in a commutative ring with identity (it is not supposed to be Noetherian). When does there exist $j \in I$ such that $\cap_{i\not= j} m_i\subseteq m_j$? Or is there any equivalent condition for this?

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    $\begingroup$ A reformulation. You have an infinite subset $Z$ of $X = Spec(A)$ with the Zariski topology, consisting of closed points. You want there to be an element $z \in Z$ which lies in the Zariski closure of $Z - \{z\}$. $\endgroup$
    – user91132
    Commented Nov 27, 2015 at 19:58

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