# Classification of 2-dimensional Alexandrov spaces

Is it possible to classify explicitly compact 2-dimensional Alexandrov spaces with curvature bounded below (either with or without boundary)?

If yes, a reference would be helpful.

EDIT: If the question is too general, may be one can classify somehow non-negatively curved compact 2-dimensional Alexandrov spaces, e.g. as pieces of convex surfaces (see my comment below). In general I would be interested to know as precise result as possible.

• Classify up to what? isometry? – ThiKu Nov 13 '15 at 7:35
• Yes. For example all non-negatively curved metrics on the 2-sphere can be realized as convex (possibly degenerate) surfaces in Euclidean 3-space (Alexandrov's theorem). May be in general there is no such a nice description. Then I am asking on the most precise result available. – MKO Nov 13 '15 at 7:54
• You can get something local in the same vein : if $X$ is an alexandrov surface with curvature $\geq\kappa$, then every point of $X$ has a neighborhood isometric ta a small piece of the boundary of a convex subset in the space form of dimension 3 and curvature $\kappa$. – Thomas Richard Nov 13 '15 at 13:08

Applying doubling theorem, we can get rid of boundary. Then pass to the universal cover. The obtained space is isometric to convex surface in the model space with curvature $\kappa$ and any motion of your original space can be extended as a motion of this surface.