Let $\mathbf{G}$ be a reductive connected linear algebraic group over a totally real global number field, say $\mathbb{Q}$. Let $\mathbb{A}=\mathbb{R}\times\mathbb{A}_f$ be the ring of rational adele. Fix a maximal compact subgroup $K_\infty$ of $\mathbf{G}(\mathbb{R})$ and an open compact subgroup $K_f$ of $\mathbf{G}(\mathbb{A}_f)$. Fix a finite dimensional complex representation $V$ of $\mathbf{G}(\mathbb{Q})$ with corresponding local system $\mathcal{V}$ on the Shimura variety $S_{K_f}=\mathbf{G}(\mathbb{Q})\backslash \mathbf{G}(\mathbb{A})/K_\infty K_f$.

Then there should be a Hecke-equivariant isomorphism $$\boxed{H^\bullet_{(2)}(S_{K_f},\mathcal{V})\cong H^\bullet(\mathfrak{g},K_\infty;L^2(\mathbf{G}(\mathbb{Q})\backslash \mathbf{G}(\mathbb{A}))^{K_f}\otimes V)}$$ between the $L^2$-cohomology and the relative Lie algebra cohomology, where $\mathfrak{g}=Lie(\mathbf{G})$.

I have found several references for this and this seems to be well-known. However, everybody refers the article of Borel and Casselman: "$L^2$-cohomology of locally symmetric manifolds of finite volume" in Duke vol 50, p. 625-647. Indeed, Proposition 5.6 in this article makes almost exactly this statement, but only for **semisimple** $\mathbf{G}$. It seems to me that the proof does not use this extra assumption.

My question: Does this isomorphism hold for arbitrary connected reductive $\mathbf{G}$?