3
$\begingroup$

I've recently been learning about the special values of symmetric square $L$-functions of modular forms.

If $f$ is a cuspidal modular eigenform (of some weight $k \ge 2$) then its symmetric square $L$-function is the $L$-function given by $\prod_{\text{$\ell$ prime}} D_\ell(\ell^{-s})^{-1}$, where for almost all $\ell$ we have $D_\ell(X) = (1 - \alpha^2 X)(1 - \alpha \beta X)(1 - \beta^2 X)$, $\alpha, \beta$ being as usual the roots of the Hecke polynomial $X^2 - a_\ell(f) X + \ell^{k-1} \varepsilon_f(\ell)$.

Now, it seems to me that the critical values of $L(\operatorname{Sym}^2 f, s)$ (in the sense of Deligne) should be the odd integers in the range $1 \le s \le k-1$, and the even integers in the range $k \le s \le 2k-2$. If you twist the symmetric square by a Dirichlet character $\chi$ with $\chi(-1) = -1$, then the parity flips and you see even integers in $\{1, \dots, k-1\}$ and odds in $\{k, \dots, 2k-2\}$.

What's puzzling me is an assertion in Hida's paper "P-adic L-functions for base-change lifts from GL(2) to GL(3)" (see link, page 93 onwards). Hida works with a different $L$-function, a shifted version of the adjoint $L$-function; so his $L$-function is $L(\operatorname{Sym}^2(f) \otimes \varepsilon_f^{-1}, s)$ in my notation. Thus the critical values of Hida's $L$-function, by my computation, should be the integers in $\{1, \dots, k-1\}$ with the opposite parity to $k$, and the integers in $\{k, \dots, 2k-2\}$ with the same parity as $k$ (so the "near-central" values $k-1$ and $k$ are always critical).

However, Hida states on p96 of his paper that the critical values of his $L$-function are the odd integers in $\{1, \dots, k-1\}$ and the even ones in $\{k, \dots, 2k-2\}$, regardless of the parity of $k$. Have I got this computation wrong, or is this a mistake in Hida's paper?

$\endgroup$
6
  • $\begingroup$ What is the answer for $k=2$? Here $s=2$ is critical. $\endgroup$
    – kantelope
    Sep 8, 2015 at 9:33
  • $\begingroup$ For $k$ even there is no difference between Hida's statement and my computations. The issue is only for $k$ odd. $\endgroup$ Sep 8, 2015 at 9:34
  • $\begingroup$ Magma claims (I know not how) that for $k=5$, the critical points are 6,8, and when I twist it by some character $\epsilon_f^{-1}$ who has $\epsilon(-1)=-1$, then they become 5,7. $\endgroup$
    – kantelope
    Sep 8, 2015 at 9:47
  • $\begingroup$ Magma agrees with me and disagrees with Hida, then. (Magma only seems to give critical values in the right half of the $s$-plane, which is weird; I can't find any description of the CriticalPoints function in the Magma docs, so it's not clear if this is intended behaviour or a bug.) $\endgroup$ Sep 8, 2015 at 9:50
  • $\begingroup$ Reading Hida, is there any link between $\chi$ at the top of page 96 and anything previous? You seem to interpret it as the character of the form, but I do not see this explicitly. $\endgroup$
    – kantelope
    Sep 8, 2015 at 10:15

1 Answer 1

3
$\begingroup$

I have not yet checked Hida's normalization, but I think you're right about the critical range.

The critical range of the symmetric square L-function is studied in C.G. Schmidt's paper "p-adic measures attached to automorphic representations of GL(3)".

Using the notation of this paper (see bottom of page 603), for any Dirichlet character $\chi$, we have $L(\mathrm{Sym}^2 f \otimes \chi, s) = L(s-k+1, \Sigma \otimes (\chi \varepsilon_f)^{-1})$. (I'm simplifying notation a bit, since the $\chi$ in the RHS should be a Grössencharakter.)

Now the critical range is given in Lemma 2.1 of this paper (up to a shift). This gives the integers in $\{1,2,\ldots,k-1\}$ with opposite parity to $k$, together with the integers in $\{k,k+1,\ldots,2k-2\}$ with same parity as $k$.

This is consistent with what we assert about $s=k-1$ in the new version of my preprint with Chida (see Remark 5.4; the weight is $k+2$ in our article).

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.