Central binomials and irrationals I suppose this is une cause perdue, but it would be nice if the following held.
Let $\theta$ be an irrational, and let $c_m = {{2m}\choose m}$, the central binomial. For a real number $r$, let $d(r)$ denote the distance from $r$ to the nearest integer (often indicated by $\| r \|$).  Is it true that for every irrational $\theta$, the Cesaro sums behave reasonably well:
$$
(*) \quad \limsup_{N\to \infty} \frac 1N \sum_{m=1}^{N} d(c_m \theta) > 0 \,?
$$
Equivalently, does there exist $c >0$---depending on $\theta$---such that 
$$
\limsup_{N\to \infty}  \frac{\left| \left\{m \leq N\left.\right| d(c_m \theta) > c\right\}\right|}N > 0\,?
$$
For almost all $\theta$, $d(c_m\theta)$ is uniformly distributed, but not for all irrational $\theta$ (since the ratio of consecutive coefficients exceeds $1$). I don't know much more about it. It's still possible (although seemingly remote) that (*) holds for all irrational $\theta$. We can also replace the central binomial terms by the Catalan numbers and the questions are probably equivalent. (An affirmative answer to either would be fine.)
A weaker version would be whether (for all irrational $\theta$)
$$
\limsup_{N\to \infty}  \frac{\left| \left\{m \leq N\left.\right| d(c_m \theta) > c\right\}\right|}{N^{1/2 + \delta}} = \infty
$$
for some $\delta > 0$ (depending on $\theta$); an affirmative answer would be useful.
 A: I don't have an answer, but I can show that it's not true if you replace $\limsup$ by $\liminf$. 
Let $F_N(\theta) = \dfrac{1}{N} \sum_{m=1}^N d(c_m \theta)$ for $\theta \in \mathbb R$.  These are continuous functions of $\theta$.  
If $\theta$ is rational $a/\prod_{j=1}^k p_j^{d_j}$, $d(c_m \theta) = 0$ when the $p_j$-adic orders $\nu_{p_j}(c_m) \ge d_j$ for all $j$, and using Kummer's theorem it's easy to prove that the fraction of $m \in \{1,2,\ldots,N\}$ for which this is true goes to $1$ as $N \to \infty$.  Thus $F_N(\theta) \to 0$ as $N \to \infty$ for rational $\theta$. 
As a consequence of this and the fact that $\{\theta: F_N(\theta) < t\}$ is open, $\{\theta: \liminf_{N \to \infty} F_N(\theta) = 0\}$ is a dense $G_\delta$.  On the other hand, since the mean of $F_N(\theta)$ over any interval goes to $1/4$ as $N \to \infty$, $\{\theta: \limsup_{N \to \infty} F_N(\theta) \ge 1/4 \}$ is also a dense $G_\delta$.  So a generic $\theta$ (in the Baire category sense) has $\liminf_{N \to \infty} F_N(\theta) = 0$ and 
$\limsup_{N \to \infty} F_N(\theta) \ge 1/4$.
