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For $i=1,2$ let $(X_i,\tau_i)$ be Hausdorff spaces such that the lattices $\tau_1, \tau_2$ are isomorphic.

Does this imply that $(X_1, \tau_1) \cong (X_2,\tau_2)$?

(This is a follow-up question to $T_2$-spaces such that the lattices of open sets can be embedded into each other.)

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    $\begingroup$ Yes, Hausdorff spaces are sober. $\endgroup$ Commented Aug 5, 2015 at 7:36

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