# Is $\liminf \frac{\sigma_{k}(n)}{n}$ finite for every $k$?

Can someone show me how to prove that $$\liminf_{n \to \infty} \frac{\sigma_{k}(n)}{n} < \infty$$ for every natural number $k$? Or is this problem open? Here, $\sigma_{k}(n)=\sigma(\sigma(\sigma(\dots n)))$ is the $k$-th iterate of the sum of divisors function.

Note: I think for $k=2$ this had been proved by Makowski and Schinzel and the limit equals $1$.

Thank you for any help.

• @Ricardo Andrade: I changed back $\sigma_k(n)$ to its originally intended meaning. For the sum of $k$-th powers of $n$ it is trivial that the liminf is infinite. – GH from MO Jul 21 '15 at 21:30
• @GH from MO, thank you very much for your correction. I apologize for my mistaken description. – Ricardo Andrade Jul 23 '15 at 20:40

It is an open problem, only known for $k=1,2$.