Suppose $X\subseteq\mathbb{R}^n$ is a convex set and that a function $g(x,y):X\times X\rightarrow\mathbb{R}_+$ is smooth, "strictly biconvex" (strictly convex in $x$ and $y$ independently but not jointly), and satisfies $g(x,y)=g(y,x)$.
Alternating optimization on $g$ in this case takes a nice form: $x_{i+1}\gets \arg\min_x g(x,x_i).$
I know alternating optimization doesn't have to converge in general. But, is there any chance to prove that $x_i\rightarrow x^\ast$ that under the symmetry and biconvexity assumptions?