8
$\begingroup$

In 1957 Kinoshita and Terasaka in their article "On unions of knots" generalized the operation of connected sum; it's called $union$.

I have several questions :

1.) If the Alexander polynomial of a prime knot $K$ is divisible by the Alexander polynomials of other knots $K^{i}$, is it true that knot $K$ can be presented as a union of two knots $K^{i}$ and $K^{j}$ with the same Alexander polynomial (it is possible that $i=j$)?

2.) If a prime knot $K$ can be presented as a union of two knots $K^{i}$ and $K^{j}$ with different Alexander polynomials, is it true that the Alexander polynomial of $K$ will be prime?

Example for first question : It's true for knots $8_{5}, 8_{10}, 8_{15}, 8_{19}, 8_{20}, 8_{21}, 9_{16}, 9_{24}, 9_{28}$.

Alexander polynomials of all this knots have a common factor $t^2-t+1$ (its Alexander polynomial of $3_{1}$). And all of these knots can be presented as a union of two $3_{1}$s.

Example for second question : It's true for knots $9_{22}, 9_{25}, 9_{30}, 9_{36}, 9_{42}, 9_{43}, 9_{44}, 9_{45}$. Alexander polynomials of all this knots are prime. And all of these knots can be presented as a union of $4_1$ and $3_{1}$.

My problem

There is a knot $9_{38}$ with Alexander polynomial $5-14t+ 19t^2-14t^3+ 5t^4$ is divisable by $t^2-t+1$, but I can't find a presentation by a union of trefoils.

I will call minimal Alexander matrix of a knot the minimal square presentation matrix of Alexander module. Knot obtained by union of two knots with the same Alexander polynomial has a special form of minimal Alexander matrix.

And I see, that minimal Alexander matrix of $9_{38}$ can not be represented in this form . What does this mean?

Thank you for your attention!


                  9_38
                  (KnotPlot image of $9_{38}$ added by J.O'Rourke.)


$\endgroup$
6
  • $\begingroup$ (I tried to fix minor grammatical issues without changing the meaning. Roll back if I overreached.) $\endgroup$ Jun 13, 2015 at 14:06
  • $\begingroup$ I tried to write this sentence in more detail. Has it become more clear? $\endgroup$
    – Alina P.
    Jun 13, 2015 at 15:35
  • $\begingroup$ Yes, thanks. (Incidentally, I cannot answer any of your questions.) $\endgroup$ Jun 13, 2015 at 16:46
  • $\begingroup$ I am afraid I have not much to contribute, but it would be nice if you could talk about the "special form of minimal Alexander matrix" of $K_1 \oplus K_2$ in relation to the minimal Alexander matrix of $K_1$ and $K_2$... then we can just read the intro of the paper and know what to do next $\endgroup$
    – wilsonw
    Jun 18, 2015 at 10:15
  • $\begingroup$ The answer to the second question is negative. In short knot $12n_88$ can be presented like the union of $5_1$ and $3_1$, but it's Alexander polynomial is not prime. Later I will present a detailed explanation. $\endgroup$
    – Alina P.
    Jun 27, 2015 at 9:22

0

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Browse other questions tagged or ask your own question.