0
$\begingroup$

Which integers $n>2$ have the following property?

There is a group $G$ such that

  • $G^n \cong G$; and
  • for all integers $k$ with $1<k<n$ we have $G^k\not \cong G$.
$\endgroup$
5
$\begingroup$

This is possible with abelian groups for any $n$; see this answer to a very similar question.

$\endgroup$

Not the answer you're looking for? Browse other questions tagged or ask your own question.