Let $B$ be a symmetric bilinear form over a Euclidean space $E$. Say that $|B(v,v)|\le c\|v\|^2$ for every $v\in E$, for some $c\ge0$. Then $$4B(v,w)=B(v+w)+B(v-w)$$ yields $2|B(v,w)|\le c(\|v\|^2+\|w\|^2)$. Replacing $v$ by $tv$, $w$ by $t^{-1}w$ and minimizing over $t$, we get $|B(v,w)|\le c\|v\|\cdot\|w\|$. Notice that we can't use Cauchy-Schwarz if $B$ is indefinite.
I am interested in symmetric $n$-linear forms $B$ over $E$.
If $B(v,\ldots,v)|\le c\|v\|^n$ for every $v\in E$, is it true that $|B(v_1,\ldots,v_n)|\le c\|v_1\|\cdots\|v_n\|$ ?
At least, there exists a constant $\gamma_n$ such that $B(v,\ldots,v)|\le c\|v\|^n$ implies $|B(v_1,\ldots,v_n)|\le \gamma_nc\|v_1\|\cdots\|v_n\|$. This is because the map which, to a homogeneous polynomial of degree $n$ over $E$, associates its polar form (a symmetric $n$-linear form) is well-defined and linear. What is the best constant $\gamma_n$ ?