Connected, maximal compact, but not $T_2$ Is there a connected topological space that is maximal compact, but not $T_2$? (A space $(X,\tau)$ is said to be maximal compact if for any topology $\tau'$ on $X$ with $\tau'\supseteq \tau$ and $\tau'\neq \tau$ we have that $(X,\tau')$ is not compact.)
 A: Let $X$ be any compactly generated connected Hausdorff space that is not locally compact and let $Y=X\cup\{\infty\}$ be its one-point compactification.  Then $Y$ is compact, connected, and not Hausdorff.  To show $Y$ is maximal compact, we must show that every compact subset $K\subseteq Y$ is closed in $Y$.  If $K\subseteq X$, then $K$ is closed in $Y$ by definition.  If $\infty\in K$, it suffices to show that $K\cap X$ is closed in $X$.  Since $X$ is compactly generated, it suffices to show that $K\cap A$ is closed for every compact subset $A\subset X$.  But any such $A$ is closed in $Y$, so $K\cap A$ is closed in $K$ and hence compact.  Since $X$ is Hausdorff, this implies $K\cap A$ is closed in $X$.
A: Yes. Let Y be any compactly generated connected Hausdorff space such that Y fails to be locally compact. Let X be the one point compactification. X is maximal compact (since compact subsets of X are closed), but X is not Hausdorff.
See for example, Example 99 from Counterexamples in Topology by Steen and Seebach.
