Division methods for divergent continued fractions I hadn't even noticed before entering the subject above the parallel with the title of an earlier question posted here titled Summation methods for divergent series.  And it's just mutatis mutandis as far as the subject line goes, but not when you get to the question.  This question is more primitive.
This is just a question posted fruitlessly on November 30th on stackexchange:
The solutions to
$$
x^2-6x+10=0 \tag 1
$$
are
$$
3\pm i\tag2.
$$
Rearranging $(1)$ just a bit, we get
$$
x = 6 -\frac{10}x \tag3
$$
and then substituting the right side of $(3)$ for $x$ within the right side we get
$$
x=6 - \cfrac{10}{6-\cfrac{10}x}
$$
and iterating we have
$$
x=6 - \cfrac{10}{6-\cfrac{10}{6-\cfrac{10}{6-\cfrac{10}{6-\cdots}}}} \tag 4
$$
(or in lowest terms
$$
x=6 - \cfrac{5}{3-\cfrac{5}{6-\cfrac{5}{3-\cfrac{5}{6-\cdots}}}} \text{ (with 3 and 6 alternating).}
$$
QUESTION: Just as one speaks of "summation methods" by which $1+2+3+4+\cdots=\dfrac{-1}{12}$, etc., might there be some "division method" by which $(4)$ is equal to $(2)$?
PS: Might one prove that this continued fraction diverges in the usual sense by proving that if it converges then it must converge to the solution of (1) (and obviously it does not)?
 A: I copy'n'paste the review by M. Znojil of the paper, Kachmar, V. S., Rusyn, B. P., Shmoĭlov, V. I., Algorithms for computing the values of continued fractions, Zh. Vychisl. Mat. Mat. Fiz. 38 (1998), no. 9, 1436--1451; translation in Comput. Math. Math. Phys. 38 (1998), no. 9, 1375–1390, MR1669146 (99m:65026): 
In a pedagogically oriented communication the authors emphasize that divergent continued fractions may be analysed in a way resembling techniques of re-summation of divergent series. Having this type of application in mind, they review existing algorithms (with a few historical comments added), compare some of their properties (number of operations needed, etc.) and illustrate their characteristic features (precision, stability and the rate of convergence) on a few tabulated numerical examples.
There is a series of Russian publications that may do what you want to do: 
Shmoĭlov, V. I.; Zayats, I. A.; Sloboda, M. Z.
{\cyr Raskhodyashchiesya nepreryvnye drobi}. (Russian. Russian summary) [Diverging continued fractions] Merkator, Lʹviv, 2000. 820 pp. ISBN: 966-7563-03-0. MR1901494 (2003h:40005). 
Shmoĭlov, V. I.
{\cyr Nepreryvnye drobi. Tom} I. (Russian) [Continued fractions. Vol. I] 
{\cyr Periodicheskie nepreryvnye drobi}. [Periodic continued fractions] Merkator, Lʹviv, 2004. 645 pp. ISBN: 966-7563-06-3. MR2058216 (2006i:40007). 
Shmoĭlov, V. I.
{\cyr Nepreryvnye drobi. Tom} II. (Russian) [Continued fractions. Vol. II] 
{\cyr Raskhodyashchiesya nepreryvnye drobi}. [Diverging continued fractions] Merkator, Lʹviv, 2004. 558 pp. ISBN: 966-7563-07-3. MR2058217 (2006i:40006). 
