17
$\begingroup$

The usual story goes like this:

Smooth picture (?):

For a smooth bijection $\phi: M \to N$ between $n$-manifolds the following is true:

  1. $\phi^{-1}$ is a local diffeomorphism a.e.

  2. Given an open set $U \subset N$ and a form $\omega \in \Omega^k(U)$ we have the equality: $\int_U \omega= \int_{\phi^{-1}(U)} \phi^*\omega$.

Satisfied with this simple and very intuitive picture I slowly came to believe that this is the most general change of variables theorem there could be. That is, until I met the following theorem in a measure theoretic context.

Theorem 1:

Let $U\subset\mathbb{R}^n$ be a measurable subset and $\phi :U\to \mathbb{R}^n$ be injective and differentiable.

$\implies$ $\int_{\phi(U)} f = \int_U f\circ\phi |\det D\phi|$ for all real valued functions $f$.

Then upon searching the internet I came by a weaker version of the inverse function theorem for everywhere differentiable functions:

Theorem 2:

Let $U \subset \mathbb{R}^n$ and $f:U \to \mathbb{R}^n$ be differentiable s.t. $Df_{x_0}$ has full rank for all $x_0 \in U$
$\implies$ $f$ is a local differentiable homeomorphism.

Which leads to the following generalization:

Differentiable picture (conjecture): For a differentiable bijection $\phi: M \to N$ between $n$-manifolds the following is true:

  1. $\phi^{-1}$ is a local differentiable homeomorphism a.e.

  2. Given an open set $U \subset N$ and a form $\omega \in \Omega^k(U)$ we have the equality: $\int_U \omega= \int_{\phi^{-1}(U)} \phi^*\omega$.

In search of a unifying picture i listed the properties a function $\phi$ must have so that the pullback wont change the value of the integral.

I. $\phi$ must be locally absolutely continuous. (otherwise it could send a null set to a positive measure set). This also establishes the almost everywhere differentiability of $\phi$.

II. $D \phi$ must have full rank almost everywhere.

If we can preform change of variables with $\phi$. What more properties must it have?

Following the connection with lipschitz functions i arrived at the following unifying conjecture:

The great conjecture:

For a locally lipschitz bijection $\phi: M \to N$ between $n$-manifolds the following is true:

  1. $\phi^{-1} $ is locally bi-lipschitz (a.e.?)

  2. Given an open set $U \subset N$ and a form $\omega \in \Omega^k(U)$ we have the equality: $\int_U \omega= \int_{\phi^{-1}(U)} \phi^*\omega$.

Is this true?

$\endgroup$
4
  • 4
    $\begingroup$ Both statements in your "initial picture" are incorrect. It's not true that $\phi$ is a local diffeomorphism almost everywhere--for example, $\phi$ could be constant on a large open set. Sard's theorem says that almost every point in $N$ is a regular value, not that almost every point in $M$ is a regular point. For 2, you need several more assumptions: first, that $M$ and $N$ are compact and oriented, so that the degree of $\phi$ makes sense; and second, that $\omega$ is compactly supported in $U$, or extends continuously to $\overline U$, or some such thing, so that the integrals make sense. $\endgroup$
    – Jack Lee
    Feb 10, 2015 at 21:49
  • 4
    $\begingroup$ The accepted answer to that question assumed that $\lbrace x | \nabla f(x) = 0 \rbrace$ has measure zero. That will generally not be the case for an arbitrary smooth surjective map. $\endgroup$
    – Jack Lee
    Feb 10, 2015 at 22:44
  • $\begingroup$ oh... Maybe it's that $D \phi$ could be singular without one of it's columns being zero. Still i find it hard to construct a smooth surjection with a set of critical points of positive measure. Nevertheless i think i'll change the question and remove that level of generality since it's really not the big issue for me. $\endgroup$
    – user195750
    Feb 10, 2015 at 22:46
  • 2
    $\begingroup$ Yes, I have two accounts since i was too shy to ask a certain question and wanted to do it anonymously. Now, thanks to my recklessness my cover is blown... $\endgroup$ Feb 10, 2015 at 22:53

1 Answer 1

5
+50
$\begingroup$

If you consider continuous injections (resp. homeomorphisms onto their range) instead of locally Lipschitz bijections (resp. locally bi-Lipschitz), then the modified conjecture is true because of Brouwer's theorem on invariance of domain, with the proviso that in (2) you should consider $n$-forms instead of $k$-forms because the domain $U$ of integration is assumed open and hence is $n$-dimensional. Formula (2) in this case is simply the change of variables formula for integrals with respect to a measure $\mu$ and its pushforward $\phi_*\mu$, once you write $n$-forms in terms of the volume measure associated to a Riemannian metric on $M$ (recall that a continuous map is always Borel measurable). Here I'm assuming $M$ and $N$ oriented for simplicity.

Otherwise (assuming back your original hypotheses), you should consider locally $k$-rectifiable subsets $U$ of the target manifold $N$ in (2) instead of $U$ open ("locally" equals "countably" if your manifolds are second countable). All that remains is to show that the inverse of $\phi$ is locally Lipschitz. This, however, needs an additional hypothesis as follows. By Rademacher's theorem, any locally Lipschitz map $\phi:M\rightarrow N$ is differentiable almost everywhere; more precisely, the (Clarke sub)differential $D\phi$ of $\phi$ is a locally bounded set-valued map which is single-valued almost everywhere. That being said, the additional hypothesis you need in your conjecture to settle part (1) is that $D\phi$ takes only non-singular values, for in this case you can invoke Clarke's inverse function theorem for Lipschitz maps (Theorem 1 of F.H. Clarke, "On The Inverse Function Theorem". Pac. J. Math. 64 (1976) 97-102). Part (2) follows immediately by using the $k$-dimensional Hausdorff measure with respect to some Riemannian metric on $M$.

Some of the comments addressed the possibility of doing away with the hypothesis of $D\phi$ being non-singular by invoking Sard's theorem. However, this does not work with so little regularity assumed from $\phi$ - a necessary hypothesis for Sard's theorem to hold true, as pointed in Sard's original paper ("The Measure of Critical Values of Differentiable Maps", Bull. Amer. Math. Soc. 48 (1942) 883-890) is that $\phi$ should be at least $\mathscr{C}^1$. $\phi$ being locally Lipschitz is not good enough - as shown by J. Borwein and X. Wang ("Lipschitz functions with maximal subdifferentials are generic", Proc. Amer. Math. Soc. 128 (2000) 3221–3229), the set of 1-Lipschitz functions $f$ such that all points in its domain are critical (in the sense that $Df$ contains zero everywhere) is generic with respect to the uniform topology. In particular, generically one cannot expect the inverse of a locally Lipschitz bijection, albeit certainly continuous, to be locally Lipschitz (even if only up to a subset of measure zero).

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.