Let me first fix the definitions.

A map $p\colon E\rightarrow B$ is called a quasi-fibration, iff the canonical inclusion $p^{-1}(b)\rightarrow hofib_b(p)$ is a weak equivalence for all for all $b\in B$.

Consider a commutative square $$ \begin{array}{ccc} Y & \to & E \cr\downarrow&&\downarrow \cr X& \to &B \end{array}. $$ Replace $E\rightarrow B$ by a fibration $E'\rightarrow B$ via the usual construction and pull back the fibration to a fibration over $X$. We then obtain a canonical map from $Y$ to the pullback. I call the diagram homotopy cartesian iff this map is a weak equivalence.

Obviously a map $p\colon E\rightarrow B$ is a quasi-fibration, iff the square $$ \begin{array}{ccc} p^{-1}(\{b\}) & \to & E \cr\downarrow&&\downarrow \cr \{b\}& \to &B \end{array} $$ is homotopy cartesian for all $b\in B$.

Can one characterize homotopy cartesian squares in terms of quasi-fibrations to obtain a statement of the shape "The square is cartesian iff a map constructed out of the square is a quasifibration"?