There are many quantities in enumerative combinatorics that grow roughly exponentially, like the Fibonacci numbers, the Catalan numbers, and the factorials; indeed, most of the functions that arise in pre-19th century combinatorics -- even ones as large as the function $n^{n-2}$, which counts spanning trees of the complete graph on $n$ vertices among other things -- in a sense grow like an ordinary exponential, inasmuch as the logarithm can be asymptotically bounded above and below by linear functions of $n$.

Over the past century enumerative combinatorialists have studied other quantities that grow faster than an ordinary exponential, associated with newer sorts of combinatorial objects, such as plane partitions, alternating sign matrices, and tilings of plane regions. In these situations one often encounters functions $f(n)$ that grow quadratic-exponentially, in the sense that $\log \log f(n)$ divided by $\log n$ converges to 2 rather than 1.

My question is, are there any exact (non-trivial) combinatorial results concerning quantities that grow like a cubic-exponential function of $n$, with $(\log \log f(n)) / (\log n)$ converging to 3 (or maybe converging to something even larger, or diverging)?

One can certainly find combinatorial problems that give rise to functions exhibiting this kind of growth, but in no cases that I am aware of (outside of trivial cases) can one actually exhibit closed formulas for these sequences, or even computationally useful recurrence relations. (If for instance a formula for $f(n)$ involves a sum of $2^n$ binomial coefficients, it's not going to enable you to compute $f(50)$, even if $f(50)$ has only a few million digits and hence is within the range of exact computer arithmetic.)

Let me stress that I'm aware that a set with $n^3$ elements has exactly $2^{n^3}$ subsets, but this is the sort of case that I intended to rule out by my use of the phrase "trivial cases".