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my question is the following one:

Let $G$ be a connected reductive algebraic group over the field of complex numbers, and let $V$ be a linear representation of $G$ obtained as the isotropy representation of some symmetric space $H/G$. Then we can associate with $V$ the so-called commuting scheme $\mathcal{C}(V)$; it is a generalization of the "usual" commuting scheme associated with the adjoint representation $\mathfrak{g}$ of $G$. For the adjoint representation $\mathfrak{g}$, it is not known whether $\mathcal{C}(\mathfrak{g})$ is always reduced. But what about $\mathcal{C}(V)$, i.e., are there any known examples where $\mathcal{C}(V)$ is not reduced? I already know that $\mathcal{C}(V)$ may be reducible (contrary to $\mathcal{C}(\mathfrak{g})$), but I found nothing concerning the possible non-reduceness.

Do you know some related literature?

Thank you in advance!

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  • $\begingroup$ One point that I might have already told you: My hope is that the generic reduceness (i.e. generic smoothness) should hold (and should even be not-so-hard-to-prove) in general for the symmetric case. $\endgroup$ Commented Nov 17, 2014 at 9:08
  • $\begingroup$ Does this paper de.arxiv.org/pdf/1206.5592.pdf prove that $ \mathcal C (\mathfrak g) $ is reduced for any $ G $? $\endgroup$ Commented Dec 12, 2014 at 10:17

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