Classifying tensor powers of tangent bundles as pullbacks of appropriate tangent bundles Assume we are given a smooth manifold $M$ and let $TM^{\otimes r}, r>1,$ be some
tensor power of its tangent bundle. 
Is there any general observation/result
saying when there exists a manifold $N$ and a smooth map $f: M \rightarrow N$ such that the pull back bundle $f^*TN$ is isomorphic to
$TM^{\otimes r}$?
This question is just a result of curiosity.
 A: the idea is the folk fact that the universal space and universal stable ** bundle can be taken to be a manifold and its tangent bundle [see proof below ]
take r=3 and let M have dim d
then N should have dimension 3d
any [stable] bundle [like the tensor power] over a d dim space [like M]  can be induced by a map into the universal space by a map which goes into the d skeleton of the universal space
the d skeleton of the universal space can be embedded in R^2d and thickened to a manifold nghd to obtain a parallizable manifold
the universal bundle over the d skeleton can be reduced to a d dim bundle using obstruction theory
the total space of this bundle pulled back to the  thickened nghd will be the N of dim 3d
its tangent bundle is isomorphic to the universal bundle [because they are stably isomorphic]
the classifying map pulls the tangent bundle back to the required bundle
this proof works for r bigger but not immediately for r=2 [but mazur thickening theory should do this case]
dennis sullivan 
**stable here means fibre dim bigger than dim base
