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I'm looking for information on explicit cubic filled Julia sets with interesting properties such as:

  • Having two different finite attractors (such as $f(z)=z^3-1.5z$)

  • Being disconnected with non-empty interior

I've skimmed the work of Branner and Hubbard (The iteration of cubic polynomials) but could not find explicit examples in the canonical forms $f(z)=z^3+az+b$ or $f(z)=z^3-3a^2z+b$.

I'm specially interested in telling apart cubic filled Julia sets that have one or two finite attractors (or periodic cycles). Since the parameter space in this case has four real dimensions, I'll settle for large open subsets for each possibility.

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    $\begingroup$ For the first, it is enough to exhibit an explicit neighbourhood of $(-\frac{3}{2},0)$ in which $z\mapsto z^3-3a^2z+b$ will have two fixed points where the derivative hav modulus less than 1. For the second, p. 156 of the Branner-Hubbard paper gives a bound on the size of the Connectedness Locus: in particular, if $|a|>2$ or $|b|>128$ then the Julia set is disconnected. Take any $(a,b)$ with $b=2a^3+a$ so that the critical point $a$ is fixed, then look nearby to find similar maps with an attracting fixed point. $\endgroup$ Commented Jul 28, 2014 at 15:32
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    $\begingroup$ Do you mean filled Julia set? If the Julia set of a rational function has non-empty interior then the Julia set is all of $P^1$. So the interior of a Julia set for a polynomial is always empty since it has a fixed point at infinity. $\endgroup$ Commented Jul 28, 2014 at 15:33
  • $\begingroup$ @DJBruce, yes, I mean filled Julia set, thanks. I've edited the question. $\endgroup$
    – lhf
    Commented Jul 28, 2014 at 16:24
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    $\begingroup$ Correction: an explicit neighbourhood of $(i\frac{\sqrt{2}}{2} ,0)$ $\endgroup$ Commented Jul 28, 2014 at 18:52
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    $\begingroup$ I participated in an REU that investigated cubic polynomials from the perspective of preperiodic points and canonical heights (the third section is on filled Julia sets). The arXiv link is arxiv.org/abs/0807.0468v3 and one interesting example is $f(z) = -\frac{25}{24}z^3 + \frac{97}{24}z + 1$; to see why, consider the forward orbit of $z = -\frac{7}{5}$... $\endgroup$ Commented Jul 29, 2014 at 3:56

3 Answers 3

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As Lasse suggests, you can draw pictures of the parameter space to help you explore the possible dynamic behavior of cubic polynomials. Any cubic polynomial is conjugate to some polynomial of the form $$f_{a,b} = z^3 - 3a^2z + b.$$ Thus, your parameter space is four-dimensional, depending on the two complex parameters $a$ and $b$. The two critical points are always $\pm a$, thus we might decompose ${\mathbb C}^2$ into the sets of points $(a,b)$ where:

  1. $a$ and $-a$ both converge to the same finite orbit (deep purple)
  2. $a$ and $-a$ both converge to different finite orbits (green)
  3. $a$ escapes to $\infty$ but $-a$ converges to a finite orbit (red)
  4. $-a$ escapes to $\infty$ but $a$ converges to a finite orbit (blue)
  5. $a$ and $-a$ both escape to $\infty$ (light)

For visualization purposes, we can fix one of $a$ or $b$ while letting the other vary within a rectangle, effectively generating a two-dimensional slice of the region. Here is such an image with $a=0.575$ while $b$ ranges within $[-1.5,1.5]\times[-1,1]$. Black indicates that the classification was unsuccessful. The image is animated with the Julia set being shown for 10 different choices of the parameter $b$.

enter image description here

I'm confident in the images. It's fairly easy, for example, to locate parameters corresponding to super-attracting orbits and to parametrize certain parts, as the main cardioid in the Mandelbrot set can be parametrized.

If we'd like to get a grip on the entire parameter space, we can generate a grid of images for different choices of $a$; within each image, $b$ varies. Here's such a grid:

enter image description here

I implemented this all in Mathematica and would be happy to share the code.

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  • $\begingroup$ Beautiful answer! Would you still be inclined in sharing the code? $\endgroup$
    – Andrea
    Commented Jun 17, 2016 at 10:28
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    $\begingroup$ @AndreaDiBiagio Sure! You can grab it here for the time being. $\endgroup$ Commented Jun 17, 2016 at 10:44
  • $\begingroup$ Got it, thanks! And cool website by the way! $\endgroup$
    – Andrea
    Commented Jun 17, 2016 at 11:25
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For the first question it is enough to exhibit an explicit neighbourhood of $(i\frac{\sqrt{2}}{2},0)$ in which $z\mapsto z^3−3a^2z+b$ will have two fixed points where the derivative have modulus less than 1. For the second, p. 156 of the Branner-Hubbard paper gives a bound on the size of the Connectedness Locus: in particular, if $|a|>2$ or $|b|>128$ then the Julia set is disconnected. Take any $(a,b)$ with $b=2a^3+a$ so that the critical point $a$ is fixed, then look nearby to find similar maps with an attracting fixed point.

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As Adam notes, having two different attracting orbits is an open property. (Moreover, these maps are stable, meaning that nearby functions have conjugate dynamics on their Julia sets.) He also gives a good way of finding explicit examples with one critical orbit diverging to infinity and having a finite periodic attracting cycle (hence disconnected but not totally disconnected Julia set).

If you would like to find a larger range of examples, then I would suggest at drawing pictures of suitable slices of parameter space. One example would be the space of real cubic polynomials, but of course you can also build one-dimensional complex spaces e.g. by introducing critical orbit relations.

You can easily write some simple heuristics to detect whether the critical points converge to attracting cycles or infinity, and if so, whether they have the same behaviour or not. Introduce a suitable colouring scheme, and this should allow you to find many different examples of the types of behaviour that you are seeking.

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