A semi-ampleness criterion for homogeneous bundles on homogeneous spaces? Let $X$ be a (compact) homogeneous space and $V$ be a homogeneous vector bundle on $X$ of rank $n$, and such that $\operatorname{dim}X\ge n$. Suppose $V$ has a section $s$, whose zeros $s=0$ form a sub-variety of $X$ of dimension $\operatorname{dim}X-n$. Is it true, that $V$ is a semi-ample vector bundle? 
 A: Yes, that is true.  By "compact homogeneous space", I assume that you mean a smooth projective variety over an algebraically closed field $k$ (presumably $\mathbb{C}$ for you) that is homogeneous under an algebraic action of a group $k$-scheme $G$ (or holomorphic action of a complex Lie group).  Let $\mathcal{F}$ be a locally free $\mathcal{O}_X$-module with an associated $G$-linearization.  Then also the locally free $\mathcal{O}_X$-module $\mathcal{F}(X)\otimes_k \mathcal{O}_X$ has a $G$-linearization, and the natural $\mathcal{O}_X$-module homomorphism, $$e : \mathcal{F}(X)\otimes_k \mathcal{O}_X \to \mathcal{F},$$ is $G$-equivariant.  
In particular, the cokernel of $e$ has an associated $G$-linearization.  There is a maximal open subscheme of $X$ over which the cokernel is locally free -- just the open set on which the rank is minimal (this uses that $X$ is reduced). Since $\text{Coker}(e)$ is $G$-linearized, this dense open subscheme is $G$-invariant.  Since $X$ is homogeneous, this dense open subscheme equals all of $X$ so that $\text{Coker}(e)$ is a locally free $\mathcal{O}_X$-module.  Thus also the image of $e$ is locally free, and the short exact sequence, $$ 0 \to \text{Image}(e) \to \mathcal{F} \to \text{Coker}(e) \to 0,$$ is locally split.  
Now, by hypothesis, $s$ is a global section of $\mathcal{F}$, and its zero scheme is nonempty of codimension $\text{rank}(\mathcal{F})$.  However, by construction of $e$, also $s$ is a global section of $\text{Image}(e)$, so that its zero scheme has codimension no greater than $\text{rank}(\text{Image}(e))$.  Hence $\text{Image}(e)$ has the same rank as $\mathcal{F}$, and $\text{Coker}(e)$ has rank $0$.  Since $\text{Coker}(e)$ is locally free, this is the zero sheaf.  Therefore $e$ is surjective and $\mathcal{F}$ is globally generated (hence semiample).  
