# Sober topological subspace

Assume $X$ to be a Notherian topological space such that any irreducible closed subset has a unique generic point. Consider $Y\subseteq X$ as a topological space with the induced topology from $X$. Is it true that any irreducible closed subset of $Y$ has a unique generic point?

What properties on $Y$ make above question to be true?

Any information even in the case that $X= \text{Spec R}$ with the Zariski topology (R is a Notherian ring) is also useful.

• Open subspaces of sober spaces are sober, as are closed subspaces. In general, not every subspace is sober. See Lemma 1.2.5 in [Sketches of an elephant, Part C]. – Zhen Lin Jun 22 '14 at 17:08

Surely not: the subspace of $\text{Spec}(\mathbb{Z})$ consisting of nonzero primes, which is homeomorphic to $\mathbb{N}$ with the cofinite topology, is not sober. See also Wikipedia.
• So if $M$ is not a finitely generated module, we still can not say any thing about being Sober of $Y=\text{Supp}_RM$ as a topological subspace of $X=\text{Spec} R$. – user49402 Jun 22 '14 at 18:21
• Yes, for example the sum of all $\mathbb{Z}/(p)$ has support given by the nonzero primes $p$. – Todd Trimble Jun 22 '14 at 19:01