0
$\begingroup$

$\{x_1,\ldots,x_n,\xi_{m+1},\ldots,\xi_n\in\mathbb{R},\xi_1=\ldots=\xi_m=0\}$ is a "model" codimension $m$ coisotropic submanifold of $T^*\mathbb{R}^n$, and is of course noncompact. Is there such a thing as a "model" compact coisotropic?

$\endgroup$
1
  • $\begingroup$ Consider $\mathbb C P ^n $ with its standard (Kaehler) symplectic structure and homogeneous coordinates $[z_0:\cdots:z_n]$. The submanifolds defined by $\Im z_j=0$ for $j=0,\ldots,m$ and $0\leq m\leq n$ are compact and coisotropic (the case $m=n$ is Lagrangian and gives $\mathbb R P ^n$). $\endgroup$ Commented Apr 12, 2014 at 13:58

1 Answer 1

1
$\begingroup$

There are well-known normal form theorems for all kind of constant rank submanifolds in symplectic manifolds, even global statements (and only such a thing seems to be of interest if you want to talk about compactness). You find these statements at many places, I personally like very much the discussion in Eckhard Meinrenken's lecture notes on symplectic geometry, available on his homepage.

$\endgroup$

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .