A small question about the necessary conditon of linear Kakeya conjecture For $0<\delta\ll 1$ we define a $\delta$-tube to be any rectangular box $T$ in $\mathbb{R}^d$ with $d-1$ sides length $\delta$ and one side of length $1$, observe that such tubes have volume $\delta^{d-1}$. Let $\mathbb{T}$ be an arbitrary collection of such $\delta$-tubes whose orientations form a $\delta-$ separated set of points on $\mathrm{S}^{d-1}$(i.e. for every direction $e_j, e_k, |e_j-e_k|\leq \delta$). If we use $\#\mathbb{T}$ to denote the cardinality of $\mathbb{T}$ , and $\chi_{T}$ to denote the indicator function of $T$, then the linear Kakeya conjecture says that for each $\frac{d}{d-1}<q\leq\infty$, there is a constant, independent of $\delta$ and the collection $\mathbb{T}$, such that 
$$
\|\sum_{T\in\mathbb{T}}\chi_{T}\|_{L^{q}(\mathbb{R}^d)}\leq C\delta^{(d-1)/q}(\#\mathbb{T})^{1/q}
$$
My first question is that which example can show that the range $\frac{d}{d-1}<q\leq\infty$ is necessary? 
Another question is the case $q=\infty$, then this estimate suggest that the LHS should be bounded, which is confusing me a little. Consider a collection of tubes passing through the origin and let the origin be the center of all tubes, then since the intersection of all tubes contains a ball of radius $\delta$, and the number of such tubes can be say $\delta^{-(d-1)}$, then we have  $\|\sum_{T\in\mathbb{T}}\chi_{T}\|_{L^{\infty}(\mathbb{R}^d)}\approx\delta^{-(d-1)}$, which is not uniformly bounded, so where am I wrong?
 A: The (full) Kakeya maximal function conjecture can be more succinctly written as
$$|| \sum_{t \in \mathbb{T}} \chi_{t} ||_{L^{\frac{d}{d-1}}(\mathbb{R}^d)} \ll_{\epsilon} \delta^{-\epsilon}.$$
Estimates (such as the one you wrote) involving the number of tubes $\#\mathbb{T}$ are only superficially stronger, thanks to factorization theory.
Note that the estimates are more interesting the smaller $q$ is. When $q=\infty$ the correct estimate is, as you observe,
$|| \sum_{t \in T} \chi_{T} ||_{L^{\infty}(\mathbb{R}^d)} \ll \delta^{-(d-1)}.$ 
The quantity is not uniformly bounded at $L^{\infty}$, as your expression above might suggest.
To see that the estimate you wrote fails when $q=\frac{d}{d-1}$ (or, in other words, one needs the $\delta^{-\epsilon}$ in the formulation I gave above)
consider the $\delta$ neighborhood of a Besicovitch set, say $B_{\delta}$.  Since a Besicovitch set contains a unit line segment in every direction, for every $t \in \mathbb{T}$ there is translate of a tube in this direction in $B_{\delta}$. Let $\sum_{t \in \mathbb{T}} \chi_{t}$ denote the function obtained from using each such tube from $B_{\delta}$. Now  $||\sum_{t \in \mathbb{T}} \chi_t||_{L^{1}} = \delta^{1-d} \delta^{d-1} = 1$, but the support of $\sum_{t \in \mathbb{T}} \chi_t$ tends to $0$ with $\delta$. It follows that $|| \sum_{t \in T} \chi_{T} ||_{L^{\frac{d}{d-1}}(\mathbb{R}^d)}  \rightarrow \infty$ as $\delta \rightarrow 0$.
There a number of expository treatments of these topics. See: Tao's course notes and Wolff's survey article on Kakeya.
