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So, if we have an infinite dimensional Hilbert space $H$ then the way you put a ring structure on $F(H)$ is by taking the isomorphism $H\oplus H \to H$ we can define the sum of two Fredholm operators as $$ H \to H \oplus H \to H \oplus H \to H$$ where the middle map is the sum of the two operators.

What is the equivalent for the ring structure? I figured it's something to do with $$ H \to H \otimes H \oplus H \otimes H \to H \otimes H \oplus H \otimes H \to H$$ but I cannot get the signs on the image map to work out. Also, is there a good reference to all this? Especially on how this works out when we switch to spectra.

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    $\begingroup$ I don't understand what the second map is supposed to be. $\endgroup$ Commented Nov 7, 2013 at 5:15
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    $\begingroup$ Have a look at Atiyah-Singer, ''Index theory for skew-adjoint Fredholm operators''. At the end of the paper, they discuss how to deal with the product structure. $\endgroup$ Commented Nov 7, 2013 at 6:43
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    $\begingroup$ I have no idea whether or not it is accessible, but I think this was studied in Marta Herrero's 1972 thesis at Chicago, ``Homology operations on H_*(BUxZ) and H_*(BOxZ) related to the tensor product of vector bundles''. She was using Fredholm operators to model the tensor product. $\endgroup$
    – Peter May
    Commented Nov 8, 2013 at 2:24
  • $\begingroup$ @JohannesEbert I really like the simplicicty of the formula for a $\mathbb{Z}_2$ graded Hilbert space. $\endgroup$ Commented Nov 8, 2013 at 18:55

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The formula is $$A \cdot B = \begin{bmatrix} A \otimes I & -I \otimes B^* \\ I \otimes B & A^* \otimes I \end{bmatrix}$$ the sign $- I \otimes B^*$ is to make associativity work out.

I found it in here: Klaus Janich. Vektorraumbundel und der Raum der Fredholm-Operatoren. Math. Ann., 161:129–142, 1965

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