Jack symmetric polynomials are known to be generalizations of Schur functions $\chi_\lambda$, for which powerful Weyl determinant formulas are known. Are there any generalizations of two determinant formulas for general Jack symmetric $P^\alpha_\lambda(x)$ functions?

The first determinant (Jacobi-Trudi) formula represents the character of the irrep GL(N) given by the partition $\lambda$ $$ \chi_\lambda(x)=\det_{i,j} s_{\lambda_i-i+j} $$ where $s_k$ are elementary Schur function and the second one gives the same function as determinant $$ \chi_\lambda(x)=\frac{\det_{i,j} x_i^{\lambda_j+N-j}}{\det_{i,j} x_i^{N-j}} $$ Jack symmetric polynomials are natural generalizations of Schur polynomials, and probably, to operate with them it would be useful to have as simple as possible analogs of Weyl formulas.


2 Answers 2


A natural analog would be a representation of the Jack polynomial as an alternating sum of eigenfunctions of the Calogero-Sutherland operator over an orbit of the symmetric group. This can be done even in the q-deformed case (i.e. for Macdonald polynomials and Macdonald operators). Such formula was conjectured by Felder and Varchenko and proved in the paper arXiv:q-alg/9603022, see formula (5-5).

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    $\begingroup$ Pavel, thank you very much for your answer. Unfortunatelly "Quantum" q-deformed polynomials are too involved for me, and, though in the classical limit relation you told me about could give one of the required formulas,I would prefer to have an "classical" explanation in terms like Calogero-Sutherland operator you mention. $\endgroup$
    – Sasha
    Feb 8, 2010 at 22:57
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    $\begingroup$ There is no difference whatsoever between the classical and quantum case. Just set q=1 and use usual Lie algebras instead of quantum groups. The arguments apply verbatim. $\endgroup$ Feb 9, 2010 at 1:30
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    $\begingroup$ At $\alpha=1$, can Jacobi-Trudi be explained as a result that follow from consideration of differential operators and eigenfunctions? $\endgroup$
    – Student
    Nov 14, 2019 at 4:32

Lassalle and Schlosser have obtained in Inversion of the Pieri formula for Macdonald polynomials some recurrence relations for MacDonald polynomials $P_\lambda(x;q,t)$ which can be restricted to Jack polynomials making $q=t^\alpha$ and letting $t\to 1$.

These recurrence relations lead to expressions for Jack polynomials as linear combination of products of elementary Schur functions, as you want. But it is not clear to me under what circumstances these relations can be written in the form of a determinant. This is true when $\lambda=(r,1^s)$ is a hook, in which case $$ P_{\lambda}^\alpha\propto\det\left(\frac{\alpha\lambda_i+s-\alpha i+j(\alpha-1)+1}{\alpha\lambda_i+s-i+1}P^\alpha_{(\lambda_i-i+j)}\right). $$


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