2
$\begingroup$

Let $X$ be a smooth projective connected complex algebraic variety with ample canonical bundle. Let $h$ be the hilbert polynomial of the canonical bundle.

Why is the moduli stack of canonically polarized varieties with hilbert polynomial $h$ of dimension $>0$? (I know that it could have a zero-dimensional connected component, think of a fake projective plane.)

In other words, I'd like to know why the existence of $X$ forces the existence of many varieties that are "like" X.

$\endgroup$
3
  • 1
    $\begingroup$ What makes you believe that there is an irreducible component of your moduli space of positive dimension? If you are asking whether or not that is true, I suggest editing your question a bit. $\endgroup$ Commented May 17, 2013 at 12:27
  • 2
    $\begingroup$ An irreducible compact quotient $X$ of a polydisc has ample canonical bundle but if its dimension is greater than one then $H^1(X,T_X)=0$, so that $X$ is rigid! See [Y. Matsushima and G. Shimura, "On the cohomology groups attached to certain vector valued differential forms on the product of the upper half planes". Ann. of Math. (2) 78 1963 417–449]. $\endgroup$
    – diverietti
    Commented May 17, 2013 at 13:16
  • 2
    $\begingroup$ Any canonically polarised surface of general type with the same Hilbert polynomial as a fake projective plane is a fake projective plane (and these are all rigid). $\endgroup$
    – naf
    Commented May 17, 2013 at 14:21

1 Answer 1

5
$\begingroup$

If $X$ is a surface, then the Hilbert polynomial of the canonical divisor determines $d:=1-\chi(T_X)$ which is a lower bound for the dimension of any component of the moduli at the point $[X]$. Hence if $d>0$ it is true that the existence of $X$ forces the existence of other varieties like it.

$\endgroup$

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .