Mayer-Vietoris Sequence for Arbitrary Bicartesian Square of Spectra Can anyone tell me if there is a Mayer-Vietoris sequence for an arbitrary homotopy pushout (hence homotopy pullback) of spectra and an arbitrary (co)homology theory. If this comes from some easy way of writing down a pushout/pullback as a fiber sequence, it'd be really cool to see that spelled out (as if I were a baby). Also, it would also be really neat to know if there are general conditions on a model category or on the (co)homology theory to make this true. 
Thanks in advance. :-) 
 A: Mayer-Vietoris sequences can be obtained from excision isomorphisms. 
Anything worthy of the name "homology theory" will give a long exact sequence 
$$\dots \to h_n(A)\to h_n(X)\to h_n(A\to X)\to h_{n-1}(A)\to \dots$$
for each morphism $A\to X$. And for a square, a.k.a. map of morphisms $(C\to B)\to (A\to X)$, it will give you a map from the long exact sequence of $C\to B$ to that of $A\to X$. 
If the square happens to induce an isomorphism $h_n(C\to B)\to h_n(A\to X)$ for every $n$ (as it will if it is a homotopy pushout square) then the desired map $h_n(X)\to h_{n-1}(C)$ is given by composing $h_n(X)\to h_n(A\to X)\cong h_n(C\to B)\to h_{n-1}(C)$, and a little diagram chase gives you the exactness you want. 
Depending on how one axiomatizes the notion of homology theory, the fact that homotopy pushout squares gives isomorphisms in relative homology is either an axiom or a consequence of the axioms. 
There is no need to work with spectra or other stable objects here.
Note that if you had something like a homology theory except that it gave isomorphisms $h_n(C\to B)\to h_n(A\to X)$ for homotopy pullbacks instead of for homotopy pushouts then you would get a "Mayer-Vietoris sequence" for pullback squares. That's how it is for homotopy groups and based spaces, except that things get funny down around $\pi_1$ and relative $\pi_2$. 
A: I didn't want to answer this because the question seemed too 
elementary to spend time on.  But to see quasicategories invoked for something
so classically elementary is truly painful. (Forgive me Dylan).  Jon asked "to see that spelled 
out (as if I were a baby)".  Here goes. The question was about spectra, and you 
place yourself in any halfway reasonable category of such.  If you are really old-fashioned your objects are CW spectra (alias cofibrant), but to have a homotopically meaningful construction we may as well use CW approximation or model theoretic cofibrant approximation to assume that $A$, $B$, and $C$ are CW or cofibrant. We have standard cylinders $A\wedge I_+$ and form the double
mapping cylinder (explicit homotopy pushout) 
$$D = B \cup (A\wedge I_+) \cup C$$ 
with cofibration 
(yes, I know, that requires just a smidgen of trivial verbiage) 
$B\vee C \longrightarrow D$ with quotient (yes, there is no problem
with quotients)  $D\longrightarrow \Sigma A$. You are in a stable situation
so the cofiber sequence extends to the left, but you can also just
look at its extension $\Sigma A\longrightarrow \Sigma B\vee \Sigma C$ to the
right to identify the maps.  This is all exactly as if you were just in based spaces, except that in a stable situation cofiber sequences are fiber sequences. Nothing at all fancy, and the argument adapts very easily to any stable model category.
Dylan, you asked about classical excision; one way that goes is to use CW approximation to replace  an excisive triad $(X;A,B)$ by a CW triad; then, with $C=A\cap B$, $X/C \cong A/C\vee B/C$. (Concise, page 110).
A: Ok, I'll state this a bit more confidently... (but I'm still worried I'm missing something).
Any time we're in, say, a stable model category where every object is cofibrant (or stable $\infty$-category), then given an object $X$ and a homotopy push-pull diagram (which I won't draw), involving $A \rightarrow B$, $A \rightarrow C$ and $C, B \rightarrow D$ we get a long exact sequence like
$$
\cdots \rightarrow [D, X] \rightarrow [B, X]\oplus [C, X] \rightarrow [A, X] \rightarrow [\Sigma^{-1} D, X] \rightarrow\cdots
$$
Indeed, we have a homotopy push-pull as above precisely if we have a (co)fiber sequence
$$
A \rightarrow B \oplus C \rightarrow D
$$
where the first map is the difference of the two obvious ones. There's probably a good way to do this without being fancy, but the easiest way I see to do this is in the setting of $\infty$-categories: the pushout and cofiber displayed above both have manifestly the same universal property. (I think I'm using cofibrancy here to say that the coproduct and homotopy coproduct should agree... maybe I don't need this- I'm bad with model categories, someone should correct me.)
Anyway, this must be in one of the obvious references. Adams? Neeman's book on triangulated categories? Something like that.
It's not immediately obvious to me that this specializes to Mayer-Vietoris, but that's me revealing too much of my ignorance. Inclusions of open subsets don't seem to be cofibrations, so why should the usual square we write down be a homotopy pullback/pushout (after taking suspension spectra)?
