2
$\begingroup$

Hi,

Could anyone explain to me how A and B are the same/different/equivalent?

A = The Siegel-Walfisz Theorem as stated in Wikipedia (this is the statement in Davenport)

http://en.wikipedia.org/wiki/Siegel%E2%80%93Walfisz_theorem

B = The Siegel-Walfisz Theorem with the error term replaced by $x/(\log x)^A$ (see, for example, Iwaniec/Kowalski page 124/419)

Thanks very much.

$\endgroup$
0

1 Answer 1

6
$\begingroup$

Version A is stronger, while Version B is easier to state as it has no condition on $q$.

Version A is usually derived from a result of Page which gives even more information (in terms of possible Siegel zeros). See Corollary 11.17 in Montgomery-Vaughan: Multiplicative number theory I.

$\endgroup$
0

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .