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Consider a K3 surface given as the double branched cover over P^2, branched along a smooth sextic. What is the ramification divisor in the K3 surface?

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The ramification divisor projects isomorphically to the plane sextic curve. Is that what you were asking?

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    $\begingroup$ and it has self-intersection equal to 18 $\endgroup$
    – rita
    Commented Aug 7, 2012 at 21:25

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