This question was inspired by the inactive thread How to find this value of $A$? but the focus there was on the divergence of the imaginary part.
It seems that for a given nonzero real $x$, $$\operatorname{Re}\frac{W_{k^2}(x)}{W_k(x)}=k+\frac14\operatorname{sgn}x+o(1)$$ where $k$ is a positive integer and $W_k(x)$ denotes the $k$th branch of the Lambert $W$ function.
When the branch index is negative, it also seems that $$\operatorname{Re}\frac{W_{-k^2}(x)}{W_{-k}(x)}=k+\frac12-\frac14\operatorname{sgn}x+o(1).$$
Are these asymptotics true?