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Does the following holds?

For every bipartite graph $H$ and every graph $G$ with $\frac{\Delta(G)}{\delta(G)}\leq 2$, $$t(H,G)\geq t(K_2, G)^{e(H)}.$$

If not sure, is this a equal question as Sidorenko's conjecture or a subquestion of Sidorenko?

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  • $\begingroup$ What does $t(H,G)$ mean? $\endgroup$
    – bof
    Commented May 1 at 18:14
  • $\begingroup$ @bof Take a random onto map f from V(H) to V(G), the prob. that this map keep adjacency, i.e. a~b implies f(a)~f(b). If G's adjacency matrix's every element is 1, then for every H t(H,G)=V(G)^V(H)/V(G)^V(H)=1. $\endgroup$
    – tom jerry
    Commented May 2 at 8:51

1 Answer 1

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Proving the conjecture for host graphs $G$ with $\Delta/\delta$ bounded is equivalent to proving the full conjecture. One may even assume that the host graph $G$ is both vertex- and edge-transitive, a result of Szegedy that can be found at https://arxiv.org/abs/1504.00858.

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