My question stems from the following result about holomorphic functions on the unit disc:
"A function, continuous on the closed unit disc, holomorphic inside, and vanishing on an open subset of the boundary, vanishes identically. A simple proof of this well-known proposition is obtained by considering its Cauchy integral representation." (Generalized Analytic Functions by Richard Arens and I.M.Singer)
There are other more direct proofs too, including the one by P.R. Chernoff, using a product of finitely many rotations of $f: \Bbb D \to \Bbb C$ and the identity theorem. See details here, for example.
In P.R. Chernoff's article, I found the statement of a stronger result - the set of zeros of $f: \Bbb D \to \Bbb C$ on $∂𝔻$ cannot have positive Lebesgue measure unless $f$ vanishes identically. The proof is more involved and can be found in Chapter 4 of Banach Spaces Of Analytic Functions by Kenneth Hoffman. See the Corollary on Pg. 52 of a Theorem on Pg. 51.
Question: It is natural to ask what happens if $\Bbb D$ is replaced by an arbitrary open (connected?) subset $\Omega \subset \Bbb C$. Does the result continue to hold, i.e., is it true that the set of zeros of a holomorphic function $f:\Omega\to \Bbb C$ on $\partial \Omega$ cannot have positive Lebesgue measure unless $f$ vanishes identically on $\Omega$? Does a weaker result hold? One may require $\Omega$ to be bounded.
Thanks a lot!