If $\zeta_K(1/2) \neq 0$ then $\zeta'_K(1/2) = 0$ if and only if
$$
\log |D_K| = (\log(8\pi) + \gamma) n + \frac\pi2 r_1,
$$
where $D_K$ is the discriminant of $K$, and
$\gamma = 0.5772156649\ldots$ is Euler's constant.
We expect that this is impossible because such an equality would give
a closed form for $\gamma$, which should not exist.
Moreover, unless some $(r_1,r_2)$ yields
$|D_K|$ surprisingly close to an integer, we expect to be able to prove
that $[K:{\bf Q}] \leq N$ is impossible in time polynomial in $N$;
for instance it takes only a few seconds in gp to do this for $N=200$
(the nearest is about $3.567 \cdot 10^{-5}$, for $(r_1,r_2) = (28,36)$).
But I doubt that we can expect to prove this for all $r_1$ and $r_2$
in the foreseeable future.
One might hope instead to prove that $\zeta'_K(1/2) \neq 0$ by showing that
$|D_K|$ would have to be too small for a number field of given $r_1,r_2$.
Unfortunately this is not known either, even under the Generalized Riemann
Hypothesis (GRH): the best we can prove is that if $\zeta_K$ satisfies GRH then
$$
\log |D_K| > (\log(8\pi) + \gamma - o(1)) n + (\frac\pi2 - o(1)) r_1
$$
as $n \to \infty$.
(The appearance of the same linear combination of $r_1$ and $r_2$
is not coincidental; see for instance these lecture notes on the
discriminant bound:
https://abel.math.harvard.edu/~elkies/M229.19/disc.pdf.)
To derive the condition on $D_K$,
start from the functional equation $\xi_K(s) = \xi_K(1-s)$ where
$$
\xi_K(s) = \Gamma(s/2)^{r_1} \Gamma(s)^{r_2}
(4^{-r_2} \pi^{-n} |D_K|)^{s/2} \zeta_K(s).
$$
(This was already suggested in the comments by edward cornfoot and reuns.)
Thus $\xi'_K(1/2) = 0$. Hence if $\zeta_K(1/2) \neq 0$ then
$\xi_K(1/2) \neq 0$, so the logarithmic derivative $\xi'_K / \xi_K$
also vanishes at $s = 1/2$. But this logarithmic derivative is
$$
\frac{r_1}{2}( \psi(1/4) - \log\pi) + r_2 (\psi(1/2) - \log 2\pi) + \frac12 \log |D_K| + \frac{\zeta'_K(1/2)}{\zeta_K(1/2)}
$$
where $\psi$ is the logarithmic derivative of the Gamma function.
Therefore $\zeta'_K(1/2) = 0$ if and only if
$$
\log|D_K| = r_1 (\log \pi - \psi(1/4) ) + 2r_2 (\log 2\pi - \psi(1/2)).
$$
Our condition then follows from the known special values
$$
\psi(1/2) = -\log 4 - \gamma, \quad \psi(1/4) = -\frac\pi2 - \log 8 - \gamma.
$$